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borishaifa [10]
3 years ago
10

After 17.1 thousand years, what percentage of the original carbon-14 would be left in an organism’s remains? After 17.1 thousand

years, what percentage of the original carbon-14 would be left in an organism’s remains? 25% 17.1% 12.5% 6.25%
Chemistry
1 answer:
hram777 [196]3 years ago
6 0

Answer:

12.5%

Explanation:

Initial percentage of carbon 14 = 100%

Final percentage = ?

Time passed = 17.1 * 1000 years = 17100 years

Half life of carbon 14 = 5,730 years.

So how many Half lives are in 17100 years?

Number of Half lives = Time passed /  Half life = 3.18 ≈ 3

First Half life;

100% --> 50%

Second Half life;

50% --> 25%

Third Half life ;

25% --> 12.5%

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Chlorine–35 has 17 protons. How many protons and neutrons does the isotope chlorine–36 have? 19 protons and 17 neutrons 17 proto
pochemuha

Answer:

17 protons

19 neutrons

Explanation:

Chlorine will always have the same amount of protons, and that would be 17 protons.

The atomic mass will change according to how many neutrons are present.

Cl - 35 is comprised of 17 protons and 18 neutrons.

We want to find Cl - 36:

We simply add 1 neutron. 18 + 1 = 19 neutrons.

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State one type of additional information that could be used to determine if these three species are closely related.
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Answer:

Study the bone structure of limbs.

Explanation:

Study the bone structure of limbs can be used to find out the relatedness and relationship among three species because the pattern of bones structure is similar but the structure is different from one another due to different environmental conditions. This study provides important and useful information whether the three species are closely related or not. If they have similar bone structure than we can say that there are more chances that they are closely related to each other.

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Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r
denis23 [38]

Answer :

(1) The frequency of photon is, 3\times 10^{10}Hz

(2) The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

Explanation : Given,

Wavelength of photon = 1.0cm=0.01m     (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of photon

\lambda = wavelength of photon

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

\nu=\frac{3\times 10^8m/s}{0.01m}

\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz    (1Hz=1s^{-1})

The frequency of photon is, 3\times 10^{10}Hz

(2) Now we have to calculate the energy of photon.

Formula used :

E=h\times \nu

where,

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})

E=1.988\times 10^{-23}J/photon

The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) Now we have to calculate the energy in J/mol.

E=1.988\times 10^{-23}J/photon

E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)

E=11.97J/mol

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Answer:

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