A student wants to make a 5.00%solution of rubidium chloride using 0.377g of the substance. what mass of water will be needed to
1 answer:
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<u>Answer:</u> The moles of oxygen and carbon dioxide in air is and
respectively
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
Given mass of atmosphere =
Average molar mass of atmosphere = 28.96 g/mol
Putting values in above equation, we get:
We know that:
Percent of oxygen in air = 21 %
Percent of carbon dioxide in air = 0.0415 %
Moles of oxygen in air =
Moles of carbon dioxide in air =
Hence, the moles of oxygen and carbon dioxide in air is and
respectively
<u>Answer:</u> The rate law of the reaction is
<u>Explanation:</u>
Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
For the given chemical equation:
Rate law expression for the reaction:
where,
a = order with respect to
b = order with respect to
Expression for rate law for first observation:
....(1)
Expression for rate law for second observation:
....(2)
Expression for rate law for third observation:
....(3)
Expression for rate law for fourth observation:
....(4)
Dividing 2 from 1, we get:
Dividing 2 from 3, we get:
Thus, the rate law becomes: