We can find the y-component of the resultant force by adding the y-components of the two 20N forces.
For a force of magnitude F and lying at an angle off the x-axis θ, the y-component of the force is given by:
Fsin(θ)
The magnitude of the two forces is 20N, and they lie at 30° and 60°, so the sum of their y-components, and therefore the y-component of the resultant force, is:
20sin(30°)+20sin(60°)
= 27.3N
Einstein's energy mass equivalence relation say that if the whole given mass is converted to energy then it would be
where
m = mass in kg
c = speed of light in m/s
this is the origination of quantum physics and by this formula we can relate the dual nature of light and particle
So correct relation above will be
Answer:
25m
Explanation:
Let's assume the Jeep attains a velocity of 36km/h ; a constant speed same with that of the car.
While the Jeep is accelerating to that speed, the car with that speed passes it.
Now we can calculate the time taken for the Jeep to attain the velocity of 36km/h on her constant acceleration.
This time is t = v/a; from Newton's Law of Motion:
a = V-U / t ; a-acceleration
V is final velocity = 36km/h
U is initial velocity 0 since the body starts from rest.
Hence t = 36000/3600 ÷ 4 = 2.5s
Note conversting from km/h to m/s we multiply by 1000/3600.
But the distance covered by the car while the Jeep just accelerates is
S = U × t = 10× 2.5 = 25m.
Note From Newton's law of Motion, distance for constant speed is defined as: U × t
Hence the Car would be 25m off the starting point just as the Jeep accelerates. It would overtake the Jeep when it just covers 25m from the Jeep starting point.
Answer:
is proved.
Explanation:
The magnetic field in the long current carrying wire is,
Here, I is the current, B is the magnetic field.
Now, by using cylindrical coordinates for the divergence of B.
Put the value of B in above equation.
Hence, it is prove that for a long current I carrying wire magnetic field divergence that is .
