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3 years ago

The material or substance that a wave moves through is called a ____

Physics

2 answers:

pshichka [43]3 years ago

7 0

1. medium
2. Type
3. Temperature

Just took the quiz

marysya [2.9K]3 years ago

4 0

Answer:

The material or substance that a wave moves through is called a MEDIUM. The medium affects the speed of the wave that passes through it. One factor that affects the speed of a wave is the TYPE of medium. Some waves move faster in solids and some waves move faster in liquids and gases. Another factor that affects wave speed is the TEMPERATURE of the medium.

Explanation:

As we know that the speed of the wave is given as

$v = \sqrt{\frac{E}{\rho}}$

here we know that

E = elasticity of the medium

$\rho$ = density of the medium

So here we know that speed of the wave will change with the elasticity of the medium which meas it is the type of medium on which the speed of wave will depends upon.

Another we can say for liquid or gas we can say that

$\frac{E}{\rho} = \frac{\gamma RT}{M}$

so speed will depends on the temperature of the medium

so here answers are

1)Medium

2)Type of medium,

3)Temperature

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Space scientists have a large test chamber from which all the air can be evacuated and in which they can create a horizontal uni

nexus9112 [7]

Answer:

the magnitude of the electric force on the projectile is 0.0335N

Explanation:

time of flight t = 2·V·sinθ/g

= (2 * 6.0m/s * sin35º) / 9.8m/s²

= 0.702 s

The body travels for this much time and cover horizontal displacement x from the point of lunch

So, use kinematic equation for horizontal motion

horizontal displacement

x = Vcosθ*t + ½at²

2.9 m = 6.0m/s * cos35º * 0.702s + ½a * (0.702s)²

a = -2.23 m/s²

This is the horizontal acceleration of the object.

Since the object is subject to only electric force in horizontal direction, this acceleration is due to electric force only

Therefore,the magnitude of the electric force on the projectile will be

F = m*|a|

= 0.015kg * 2.23m/s²

= 0.0335 N

Thus, the magnitude of the electric force on the projectile is 0.0335N

3 0

3 years ago

Read 2 more answers

A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.

MakcuM [25]

Answer:

b. 9.5°C

Explanation:

$m_i$ = Mass of ice = 50 g

$T_i$ = Initial temperature of water and Aluminum = 30°C

$L_f$ = Latent heat of fusion = $3.33\times 10^5\ J/kg^{\circ}C$

$m_w$ = Mass of water = 200 g

$c_w$ = Specific heat of water = 4186 J/kg⋅°C

$m_{Al}$ = Mass of Aluminum = 80 g

$c_{Al}$ = Specific heat of Aluminum = 900 J/kg⋅°C

The equation of the system's heat exchange is given by

$m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C$