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marusya05 [52]
3 years ago
9

During a race, a runner runs at a speed of 6 m/s. 2 seconds later, she is running at a speed of 10 m/s. What is the runner’s acc

eleration? Show your work.
Physics
1 answer:
Lapatulllka [165]3 years ago
5 0
Let's calculate the average acceleration. It is the rate of changing speeds. Hence, we need to calculate the difference of speeds. 10-6=4 m/s. The rate is now \frac{4m/s}{2s} =2m/s^2.
In general, the formula for the mean acceleration between two times 1 and 2 is given by:
\frac{u_2-u_1}{T} where v1 and v2 are the speeds at the respective points and T is the time interval between them.
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What happens to the distance between interference fringes if the separation between two slits is increased?
kolezko [41]

Answer:

It will decrease

Explanation:

The double-slit interference equation, which gives us the position y of a maximum on the screen (measured relative to the central position), is

y=\frac{n\lambda D}{d}

where

n is the order of the maximum

D is the distance between the slits and the screen

\lambda is the wavelength of the light

d is the separation between the two slits

From the formula, we see that y is inversely proportional to d: this means that if the separation between the slits is increased, the distance of each maximum from the central position (y) decreases, therefore the distance between the interference fringes will decrease.

3 0
3 years ago
The table represents the speed of a car in a northern
Sidana [21]

Answer:

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4 0
3 years ago
Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton
pishuonlain [190]

Hello!

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton force is applied to it.

Data:

Hooke represented mathematically his theory with the equation:

F = K * Δx  

On what:

F (elastic force) = 2 N

K (elastic constant) = 4 N/cm

Δx (deformation or elongation of the elastic medium or distance from a spring) = ?

Solving:


F = K * \Delta{x}

2\:N = 4\:N/cm*\Delta{x}

4\:N/cm*\Delta{x} = 2\:N

\Delta{x} = \dfrac{2\:\diagup\!\!\!\!\!N}{4\:\diagup\!\!\!\!\!N/cm}

simplify by 2

\Delta{x} = \dfrac{2}{4}\frac{\div2}{\div2}

\boxed{\boxed{\Delta{x} = \dfrac{1}{2}\:cm}}\Longleftarrow(distance)\end{array}}\qquad\checkmark

Answer:

B.) 1/2 cm

_______________________

I Hope this helps, greetings ... Dexteright02! =)

7 0
3 years ago
A person should power walk for minutes a day in order to benefit from this activity
larisa86 [58]
A person should power walk 30-45 min a day
3 0
3 years ago
Read 2 more answers
a quarterback throws a football with angle of elevation 40degrees and speed 60ft/s. Find the horizontal and vertical components
pshichka [43]
<span>
the horizontal velocity would be equal to
Vh = sin (40) /60
= 0.74 * 60
= 44
</span>
the Vertical velocity would be equal to
<span>Vv = cos(40) * 60
=40</span>
4 0
3 years ago
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