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Karo-lina-s [1.5K]
3 years ago
5

Given the following skeleton equation, what are the coefficients for the chemicals in the reaction? __H20 + __ P4O10 = __ H3PO4

Chemistry
1 answer:
AysviL [449]3 years ago
4 0
6H2O + P4O10 = 4H3PO4
Coefficients: 6, 1, 4
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The stationary state with the lowest energy is called the _______.
Olegator [25]

Answer:

Ground state

the state with the smallest amount of energy.

3 0
3 years ago
How are saturated and supersaturated solutions similar?
Serggg [28]

Answer:

They are similar in sense that both cannot dissolve any more solid unless heat or other factors are added. For eg if a solution is saturated it can no longer dissolve the given substance. But if the solution is heated, the solid will dissolved this is now said to be supersaturated.

Explanation:

4 0
3 years ago
How many grams of iron can be made with 21.5g of Fe2O3
SIZIF [17.4K]

The mass (in grams) of iron, Fe that can be made from 21.5 g of Fe₂O₃ is 15.04 g

We'll begin by writing the balanced equation for the reaction. This is given below:

2Fe₂O₃ -> 4Fe + 3O₂

  • Molar mass of Fe₂O₃ = 159.7 g/mol
  • Mass of Fe₂O₃ from the balanced equation = 2 × 159.7 = 319.4 g
  • Molar mass of Fe = 55.85 g/mol
  • Mass of Fe from the balanced equation = 4 × 55.85 = 223.4 g

From the balanced equation above,

319.4 g of Fe₂O₃ decomposed to produce 223.4 g of Fe

<h3>How to determine the mass of iron, Fe produced</h3>

From the balanced equation above,

319.4 g of Fe₂O₃ decomposed to produce 223.4 g of Fe

Therefore,

21.5 g of Fe₂O₃ will decompose to produce = (21.5 × 223.4) / 319.4 = 15.04 g of Fe

Thus, 15.04 g of Fe were produced.

Learn more about stoichiometry:

brainly.com/question/9526265

#SPJ1

5 0
1 year ago
The concentration of carbon monoxide (CO), a common air pollutant, is found in a room to be 5.7 x 10^-3 mg/cm^3. How many grams
damaskus [11]

The amount, in mg, of CO present in the room will be 191,520 mg.

<h3>Stoichiometric problem</h3>

The concentration of the gas in the room is 5.7 x 10^{-3} mg/cm3.

The dimension of the room is 3.5 m x 3.0 m x 3.2 m. This is equivalent to 350 cm x 300 cm x 320 cm.

We can obtain the volume of the room as:

                  350 x 300 x 320 = 33,600,000 cm3

The concentration is in mg/cm3, meaning that it is mass/volume.

Thus:

 mass = concentration x volume = 5.7 x 10^{-3} mg/cm3 x 33,600,000 cm3

                         = 191,520 mg

The mass of CO in the room is 191,520 mg

More on stoichiometric problems can be found here: brainly.com/question/14465605

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5 0
1 year ago
In chemical reactions, how does the valence configuration of bromine tend to change?
Strike441 [17]

Answer: Near the Protons. The electron structure of bromine is illustrated above. In chemical reactions, how does the valence configuration of Bromine tend to change? ... It loses one electron.

Explanation:

btw i found that on google lol

3 0
3 years ago
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