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kari74 [83]
3 years ago
15

What is the mass of the missing reactant in the following reactions, given that the reaction goes to completion? Do not include

units.
- 2.7 g water + ________ g carbon dioxide --> 9.3 g carbonic acid
- 32.0 g sodium hydroxide + 16.0 g hydrofluoric acid --> ________ g water + 33.6 g sodium fluoride
- 0.60 g calcium carbonate + 0.48 g sodium hydroxide --> ________ g sodium carbonate + 0.45 g calcium hydroxide
- 0.53 g sodium hydroxide + 0.37 g carbon dioxide --> ________ g sodium hydrogen carbonate
Chemistry
1 answer:
N76 [4]3 years ago
6 0
1) <span> 2.7 g water + 6,6 g carbon dioxide </span>→<span> 9.3 g carbonic acid.
According to </span><span>principle of mass conservation mass of reactants and products are the same after chemical reactio. 2,7 g + 6,6 g = 9,3 g.
2) </span><span>32.0 g sodium hydroxide + 16.0 g hydrofluoric acid --> 14,4 g water + 33.6 g sodium fluoride.
m(water) = 32 g + 16 g - 33,6 g.
3) </span><span>0.60 g calcium carbonate + 0.48 g sodium hydroxide --> 0,63 g sodium carbonate + 0.45 g calcium.
m(sodium carbonate) = 0,6 g + 0,48 g - 0,45 g.
4) </span><span>0.53 g sodium hydroxide + 0.37 g carbon dioxide --> 0,9 g sodium hydrogen carbonate.
m(sodium hydrogen carbonate) = 0,53 g + 0,37 g = 0,9 g.</span>
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Answer: The possible molecular formula will be CO_2

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Step 1 : convert given masses into moles.

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