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lapo4ka [179]
3 years ago
6

A 5kg particle moving at a speed of 10m/s to the right makes an elastic collision with a wall and rebounds backward calculate th

e magnitude of the impulse of the body
Physics
1 answer:
worty [1.4K]3 years ago
7 0

Answer:

The magnitude of the impulse experienced by the particle is 100 kg.m/s.

Explanation:

Given;

mass of the particle, m = 5 kg

initial velocity of the particle, v₁ = 10 m/s

assuming the particle rebounds with same velocity backwards, v₂ = - 10 m/s

The impulse experienced by the particle is the change in linear momentum;

J = ΔP = mv₁ - mv₂

J = m(v₁ - v₂)

J = 5 (10 - (-10))

J = 5 (10 + 10)

J = 5(20)

J = 100 kg.m/s

Therefore, the magnitude of the impulse experienced by the particle is 100 kg.m/s.

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Answer:

0N

Explanation:

When you draw a free body diagram, You have a 7N arrow pointing left, and a 3N arrow pointing right. When you subtract the two, you still have a force of 4N on the left. However, seeing as how gravity is in play at a force of 4N, the two forces cancel out and you get 0N.

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A roller coaster moves 200 ft horizontally, then rises 135 ft at an angle of 30.0° above the horizontal. Next, it travels 135 f
vekshin1

Answer:

171 ft

Explanation:

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AC;  Cos 60 = AC ÷ 135

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Hi There! :)

<span>Examples of the period, frequency, speed of a wave in a sentence?

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<h2>Movement of Continents</h2>

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