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Nookie1986 [14]
3 years ago
13

A motorcyclist travels with an average speed of 6 m/s . If the cyclist is going to a friend's house 36 m away , how much time wi

ll it take the cyclist to arrive ?​
Physics
1 answer:
vodka [1.7K]3 years ago
5 0

Answer:

<h2>6 s</h2>

Explanation:

The time taken by the cyclist can be found by using the formula

t  = \frac{d}{v}  \\

v is the velocity

d is the distance

From the question we have

t =  \frac{36}{6}  \\  = 6

We have the final answer as

<h3>6 s</h3>

Hope this helps you

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1) 29.4 N

The force of gravity between two objects is given by:

F=G\frac{Mm}{r^2}

where

G is the gravitational constant

M and m are the masses of the two objects

r is the separation between the centres of mass of the two objects

In this problem, we have

M=5.97\cdot 10^{24} kg (mass of the Earth)

m=3.0 kg (mass of the box)

r=R=6.37\cdot 10^6 m (Earth's radius, which is also the distance between the centres of mass of the two objects, since the box is located at Earth's surface)

Substituting into the equation, we find F:

F=\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24})(3.0)}{(6.37\cdot 10^6)^2}=29.4 N

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Let's now calculate the ratio F/m. We have:

F = 29.4 N

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\frac{F}{m}=\frac{29.4}{3.0}=9.8 N/kg = 9.8 m/s^2

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