Question

The position of the following moving along a straight line at any time t is given by s(t) = t^2 +4t+4/ What is the acceleration of the particle when t =4?

Answer 1

Answer:

$\boxed{s(t) = 36 {ms}^{ - 2} }$

Step-by-step explanation:

$s(t) = t^2 +4t+4 \\ when \: t =4 \\ s(t) = {4}^{2} + (4)(4) + 4 \\ s(t) = {4}^{2} + {4}^{2} + 4 \\ s(t) = 32 + 4 \\ s(t) = 36$