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Andreas93 [3]
3 years ago
5

An archer aims his arrow directly at an orange hanging on an orange tree. At the moment he releases the arrow, the orange drops

off the tree. Would the arrow hit the orange? You need to show your work to justify your argument.

Physics
2 answers:
Elena L [17]3 years ago
6 0

Answer:

Yes it would

Explanation:

As the arrow and the orange are in the same position initially, vertically speaking. They are also subjected to the same gravitational acceleration g only in the vertical direction. They also start their motion at the same time. So their equation of motion can be written as

y = h + gt^2/2

Where h is the initial height of both of them. Since their g, h, and t are the same, their vertical position must be the same at the same time. As the arrows progress horizontally, it would hit the orange.

garri49 [273]3 years ago
4 0

Answer:

Yes. In this problem the two bodies are always in projectile motion: the arrow and the orange. The arrow and the orange have different initial positions and velocities, but they go into projectile motion at the same time. In order to show that the arroow always hit the orange, we have to prove that the arrow and orange have the same position along the x and y axis. See attachment.

Explanation:

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Alecsey [184]

Answer:0.1759 v

Explanation:

Intensity of wave at receiver end is

I=\frac{P_{avg}}{A}

I=\frac{3.80\times 10^3}{4\times \pi \times \left ( 4\times 1609.34\right )^2}

I=7.296\times 10^{-6} W/m^2

Amplitude of electric field at receiver end

E_{max}=\sqrt{2I\mu _0c}

Amplitude of induced emf

=E_{max}d

=\sqrt{2\times 7.29\times 10-6\times 4\pi \times 3\times 10^8}\times 0.75

=17.591\times 10^{-2}=0.1759 v

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If a man weighs 900 n on the earth, what would he weigh on jupiter, where the acceleration due to gravity is 25.9 m/s2?
balandron [24]
<span>So, if the man weight 900 newtons on Earth then that means, using F=ma, that the mass of the man is approximately 91.84 kg. This is because 900N=m(9.8m/s^2), and so it follows that 900/9.8=91.84. Using the man's found mass we then plug this into F=ma again. It follows that F=(91.84)(25.9)=2378.57N. This means that the man "weighs" 2378.57 Newtons on Jupiter, or about 2.5x as great as his weight on Earth. This makes sense, considering that 25.9/9.8 is approximately equal to 2.64.</span>
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