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NNADVOKAT [17]
3 years ago
14

Which scale is being described? Water freezes at 32 . Water freezes at 0 . Water freezes at 273 .

Physics
2 answers:
sasho [114]3 years ago
7 0

In Fahrenheit scale water freezes at 32°. In Celsius scale water freezes at 0°. and kelvin scale water freezes at 273.

Three most commonly  used temperature scale are Celsius scale, Fahrenheit scale and kelvin scale. The freezing point and boiling point of water on Celsius scale are 0° C and 100°C at sea level. The freezing point and boiling point of water on Fahrenheit scale are 32° F and 212°F at sea level. The freezing point and boiling point of water on kelvin scale are 273 K and 373 K at sea level.

chubhunter [2.5K]3 years ago
5 0
Fahrenheit
Celsius
Kelvin (Absolute)
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accelerate / increase speed OR decelerate / decrease speed OR stop B1

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Explanation:

accelerate / increase speed OR decelerate / decrease speed OR stop B1

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3 years ago
Which nucleus completes the following equation?
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Answer: ^{50}_{25}Mn\rightarrow ^{0}_1e+ ^{50}_{24}Cr

The chromium nucleus will complete the reaction.

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The given reaction is a type of radioactive nuclei decay:

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_A^Z\textrm{X}\rightarrow _{Z-1}^A\textrm{Y}+_{+1}^0e

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4 0
3 years ago
Read 2 more answers
How are electric and magnetic forces the same? How are they different?
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A 52.0-kg person, running horizontally with a velocity of +3.63 m/s, jumps onto a 15.2-kg sled that is initially at rest. (a) Ig
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Answer:

The coefficient of kinetic friction between the sled and the snow is 0.0134

Explanation:

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M = mass of person = 52 kg

m = mass of sled = 15.2 kg

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u = initial velocity of sled = 0 m/s

After collision, the person and the sled would move with the same velocity V.

a) According to law of momentum conservation:

Total momentum before collision = Total momentum after collision

MU + mu = (M + m)V

V=\frac{MU+mu}{M+m}

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V=\frac{MU+mu}{M+m}=\frac{52(3.63)+15.2(0)}{52+15.2} =2.81m/s

The velocity of the sled and person as they move away is 2.81 m/s

b) acceleration due to gravity (g) = 9.8 m/s²

d = 30 m

Using the formula:

V^2=2\mu(gd)\\\mu=\frac{V^2}{2gd} \\\mu=\frac{2.81^2}{2*9.8*30} =0.0134

The coefficient of kinetic friction between the sled and the snow is 0.0134

3 0
3 years ago
A bird flies 3.7 meters in 46 seconds, what is its speed?
victus00 [196]

Answer:

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Given the distance that the bird flies = 3.7 meters

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Speed = 3.7 / 46 = 0.08 m/s

8 0
3 years ago
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