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sleet_krkn [62]
3 years ago
8

To prepare 300.0 ml of 0.2 m nacl how many grams of nacl should be weighed out?

Chemistry
1 answer:
Leokris [45]3 years ago
8 0
One mole of NaCl weighs 58.44 grams
Therefore 1L of one mole of NaCl contains 58.44 grams
1L of 0.2m NaCl contains 58.44x0.2 = 11.69grams
300mL of 0.2m NaCl contains 11.69x0.3 = 3.51 grams
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I think the correct answer would be A. When a polonium atom with 84 protons, 124 neutrons, and 84 electrons undergoes alpha decay, a lead atom would be produced with 82 protons, 122 neutrons, and 84 electrons together with an alpha particle having two protons and two neutrons.
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Hank's Garage has an air compressor with a holding tank that contains 200L of compressed air at 5200 torr. One day a hose ruptur
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Hank's Garage has an air compressor with a holding tank that contains 200L of compressed air at 5200 torr. One day a hose ruptured and all the compressed air was released to a volume of 1370 L at atmospheric pressure.

Hank's Garage has an air compressor with a holding tank that contains a volume of 200L (V₁) of compressed air at a pressure of 5200 torr (P₁).

One day a hose ruptured and all the compressed air was released. The final pressure was the atmospheric pressure (1 atm = 760 torr) (P₂).

We can calculate the new volume (V₂) in these conditions using Boyle's law, which states there is an inverse relationship between the volume and the pressure of an ideal gas.

P_1 \times V_1 = P_2 \times V_2\\\\V_2 = \frac{P_1 \times V_1}{P_2} = \frac{5200 torr \times 200L}{760torr} = 1370 L

Hank's Garage has an air compressor with a holding tank that contains 200L of compressed air at 5200 torr. One day a hose ruptured and all the compressed air was released to a volume of 1370 L at atmospheric pressure.

Learn more: brainly.com/question/1437490

4 0
3 years ago
Gaseous neon has a density of 0.900 g/L at standard conditions. How many neon atoms are in 1.00 L of neon gas at standard condit
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Answer: 1.348 ×10^23 atoms

Explanation:

Given that volume = 1.00L

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Where avogrado's constant = 6.02×10²³

22.4 = number of atoms/6.02×10²³

Number of atoms = 1.348×10^25atoms

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Explanation:

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