1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
FinnZ [79.3K]
3 years ago
5

A woman can row her canoe at 2.5 m/s. If she faces an opposing current of 3.0 m/s, how fast will she go forward?

Physics
1 answer:
taurus [48]3 years ago
8 0

Answer:

V = - 0.5 [m/s]

Explanation:

In order to solve this problem, we must use the principle of relative speeds. This is for an observer who is on the edge of the river he can see how the river moves to the left and the woman tries to move to the right but can not since:

V_{total}=-3+2.5\\V_{total}=-0.5 [m/s]

That is, the person sees how the woman moves to the left but with avelocity of 0.5 [m/s] to the left

You might be interested in
How do I find the approximate velocity of "the object", on the graph at 5 seconds?
MakcuM [25]

First, foremost, and most critically, you must look at the graph, and critically
examine its behavior from just before until just after the 5-seconds point.

Without that ability ... since the graph is nowhere to be found ... I am hardly
in a position to assist you in the process.


7 0
4 years ago
A student of mass 40kg takes 10s to run up a flight of 50steps. If each step is 15cm high, calculate the Potential Energy of the
astra-53 [7]

Answer:

2943 J

Explanation:

Potential energy = mass x acceleration due to gravity x height in meters

(P.E. = mgh)

Substitute the given numbers: (I take acceleration due to gravity as 9.81 m s^-2)

PE = 40 x 9.81 x (0.15x50)

PE = 2943 J

3 0
4 years ago
Situation 6.1 A 13.5-kg box slides over a rough patch 1.75 m long on a horizontal floor. Just before entering the rough patch, t
GenaCL600 [577]
B) 14.0 N    

The way to solve this problem is to determine the kinetic energy the box had before and after the rough patch of floor. The equation for kinetic energy is: 

 E = 0.5 M V^2 

 where 

 E = Energy 

 M = Mass 

 V = velocity   

 Substituting the known values, let's calculate the before and after energy. 

 Before: 

 E = 0.5 M V^2 

 E = 0.5 13.5kg (2.25 m/s)^2 

 E = 6.75 kg 5.0625 m^2/s^2 

 E = 34.17188 kg*m^2/s^2 = 34.17188 joules   

 After: 

 E = 0.5 M V^2 

 E = 0.5 13.5kg (1.2 m/s)^2 

 E = 6.75 kg 1.44 m^2/s^2 

 E = 9.72 kg*m^2/s^2 = 9.72 Joules   

 So the box lost 34.17188 J - 9.72 J = 24.451875 J of energy over a distance of 1.75 meters. Let's calculate the loss per meter by dividing the loss by the distance.   

 24.451875 J / 1.75 m = 13.9725 J/m = 13.9725 N   

 Rounding to 1 decimal place gives 14.0 N which matches option "B".
8 0
3 years ago
A jet moving at 500.0 km/ h due is in a region where the wind is moving at 120.0 km/h in a direction 30.00° north of east. What
WARRIOR [948]

Answer:

The speed of the aircraft relative to the ground is 606.9 m/s^2

Explanation:

x-y coordinate system:  

x is Positive due East direction. Similarly  y is Positive due North Direction.

Now let us Decompose each vector into x-y

500 km/h due east = (500, 0)

120 km/h at 30 degree north of east

= (120 cos(30), 120 \times sin(30))

= (120 \times \frac{\sqrt{(3)}}{2}, 120 \times \frac{1}{ 2})

= (60 \times \sqrt(3), 60)

Adding  the vectors.

=(500, 0) + (60 \times \sqrt{3}, 60)

=(500 + 60 \times \sqrt(3), 60)

=(500 + 60 \times 1.73, 60)

=(500 +103.8, 60)

= (603.8, 60)

Returning back to polar form

Magnitude = \sqrt{603.923^2 + 60^2} = 606.9

7 0
3 years ago
I WILL GIVE BRAINLIEST TO WHOEVER GETS THIS QUESTION CORRECT!!!
luda_lava [24]

Answer: c) The line shows a change in speed if its angle changes.

I'm not sure

Explanation:

4 0
3 years ago
Other questions:
  • A long, straight wire carries a current of 8.60
    10·1 answer
  • What is meant in astronomy by the phrase "adaptive optics?
    11·1 answer
  • Which would be most reliable source for information about the toxity of an industrial chemical
    13·2 answers
  • An insect 5.00 mm tall is placed 20.0 cm to the left of a thin planoconvex lens. The left surface of this lens is flat, the righ
    13·1 answer
  • Need help ASAP please Thanks
    5·1 answer
  • Please help quick please
    5·1 answer
  • Pls someone help me!!!!!
    9·2 answers
  • Which example demonstrates constant speed with changing direction?
    14·1 answer
  • The diagram shows the electric field near conducting sphere a which of the following statements is correct
    15·1 answer
  • A car is traveling along a straight road at a velocity of 30m/s when its engine cuts off. For the next ten seconds, the car slow
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!