You need 5 blocks of the smaller object to contain the same amount of volume of the bigger object
It depends on the type of interference.
For constructive interference, add the amplitudes to get |35 + 41| = 76 units.
For destructive, subtract them |35 - 41| = 6 units
Answer:
Explanation:
Impulse results in a change of momentum
FΔt = mΔV
F = mΔV/Δt
The impulse acting on the hammer will equal the impulse acting on the nail
If we assume upward is the positive direction
F = m(vf - vi)/t
F = 1.2(1.0 - (-1.5)) / 0.001
F = 3000 N
Answer:
0.686 g of ice melts each second.
Solution:
As per the question:
Cross-sectional Area of the Copper Rod, A = 
Length of the rod, L = 19.6 cm = 0.196 m
Thermal conductivity of Copper, K = 
Conduction of heat from the rod per second is given by:

where
= temperature difference between the two ends of the rod.
Thus

Now,
To calculate the mass, M of the ice melted per sec:

where
= Latent heat of fusion of water = 333 kJ/kg

I would say D) melting point.