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FinnZ [79.3K]
2 years ago
5

A woman can row her canoe at 2.5 m/s. If she faces an opposing current of 3.0 m/s, how fast will she go forward?

Physics
1 answer:
taurus [48]2 years ago
8 0

Answer:

V = - 0.5 [m/s]

Explanation:

In order to solve this problem, we must use the principle of relative speeds. This is for an observer who is on the edge of the river he can see how the river moves to the left and the woman tries to move to the right but can not since:

V_{total}=-3+2.5\\V_{total}=-0.5 [m/s]

That is, the person sees how the woman moves to the left but with avelocity of 0.5 [m/s] to the left

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If the potential due to a point charge is 490 V at a distance of 10 m, what are the sign and magnitude of the charge?
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Answer:

+5.4×10⁻⁷ C

Explanation:

Electric potential: This can be defined as the work done in bringing a unit charge from infinity to that point against the action of the field. The S.I unit of potential is volt (V)

The formula for potential is

V = kq/r............................ Equation 1

Where V = electric potential, k = proportionality constant, q = charge, r = distance.

making q the subject of the equation,

q = Vr/k............................ Equation 2

Given: V = 490 V, r = 10 m,

Constant: k = 9×10⁹ Nm²/C²

Substitute into equation 2

q = 490(10)/(9×10⁹)

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