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Deffense [45]
3 years ago
5

which of the following cannot be increased by using a machine of some kind? work, force, speed, torque

Physics
1 answer:
Lemur [1.5K]3 years ago
8 0

Explanation:

Work cannot be increased by using a machine of some kind.

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Post Test: Forces and Motion
Len [333]

Answer: B to C

Explanation: The line is curving inwards, practically calculating the stance that it had went down. If it went straight across, it stayed the same till a specific point, furthermore calculating the bent line bending upwards is actually a partial-raise, conclude points B to C is most likely an un-even balance, meaning it had went down; or decreasing. B to C is the decreasing segment of this equation/problem (question).

8 0
3 years ago
Two charged particles separated by a distance of = 3 and experienced electrostatic forces of = 60 . What would be this force if
klemol [59]

Answer: 539.4 N

Explanation:

Let's begin by explaining that Coulomb's Law establishes the following:  

"The electrostatic force F_{E} between two point charges q_{1} and q_{2} is proportional to the product of the charges and inversely proportional to the square of the distance d that separates them, and has the direction of the line that joins them"

What is written above is expressed mathematically as follows:

F_{E}= K\frac{q_{1}.q_{2}}{d^{2}} (1)

Where:

F_{E}=60 N  is the electrostatic force

K=8.99(10)^{9} Nm^{2}/C^{2} is the Coulomb's constant  

q_{1} and q_{2} are the electric charges

d=3 m is the separation distance between the charges  

Then:

60 N= 8.99(10)^{9} Nm^{2}/C^{2}\frac{q_{1}.q_{2}}{(3 m)^{2}} (2)

Isolating q_{1} and q_{2}:

q_{1}q_{2}=6(10)^{-8} C^{2} (3)

Now, if we keep the same charges but we decrease the distance to d_{1}=1 m, (1) is rewritten as:

F_{E}=8.99(10)^{9} Nm^{2}/C^{2}\frac{6(10)^{-8} C^{2}}{(1 m)^{2}} (4)

Then, the new electrostatic force will be:

F_{E}= 539.4 N (5) As we can see, the electrostatic force is increased when we decrease the distance between the charges.

4 0
3 years ago
The phases of the moon depend on how much of the lighted side of the moon can be seen from earth.is this true or false
Sindrei [870]
The answer to this question is going to be False 

6 0
3 years ago
Someone help me please!!
patriot [66]
Pretty sure it's C) condensation because all of the others required heat to be added
7 0
3 years ago
Read 2 more answers
What If? The coil and applied magnetic field remain the same, but the circuit providing the current in the coil is now changed.
RUDIKE [14]

Answer:

Using equations

R will be 1.25 Kilo ohm

5 0
3 years ago
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