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2 years ago

What is thermal energy.

Physics

2 answers:

REY [17]2 years ago

7 0

Explanation:

thermal energy refers to the energy contained within a system that is responsible for its temperature. Heat the flow of thermal energy

Kamila [148]2 years ago

6 0

The term 'thermal energy' is used differently, and often loosely, in different contexts. It refers to several distinct physical concepts, such as the internal energy, or as the enthalpy, of a body of matter and radiation; or as heat, defined as a type of energy transfer (as is thermodynamic work); or as the characteristic energy of a degree of freedom,
k
B
T
{\displaystyle k_{\mathrm {B} }T}, in a system that is described in terms of its microscopic particulate constituents, where
T
T denotes temperature and
k
B
k_{\mathrm{B}} denotes the Boltzmann constant.

I learned this last week in my Sci-tech class!

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an object which has a mass of 70 kg is sitting on a cliff 10 m high calculate the objects gravitational potential energy given g

Alex73 [517]

GPE = mgh (for objects close to earth where g can be considered to be constant) Where m is the mass, g is the acceleration due to gravity (which the question has told us to assume is 10ms^-2), and h is the height of the object.

Substituting the values in:
GPE = 70*10*10 = 7000J

5 0

3 years ago

A 25.0-gram bullet enters a 2.25-kg watermelon with a speed of 220 m/s and exits the opposite side with a speed of 110 m/s. If t

umka21 [38]

Answer:

3.67 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

mu+m'u' = mv+m'v'............................... Equation 1

Where m = mass of the bullet, m' = mass of the watermelon, u = initial velocity of the bullet, u' = initial velocity of the watermelon, v = final velocity of the bullet, v' = final velocity of the watermelon.

make v' the subject of the equation,

v' = (mu+m'u'-mv)/m'....................... Equation 2

Given: m = 25 g = 0.025 kg, u = 220 m/s, m' = 2.25 kg, u' = 0 m/s ( at rest), v = 110 m/s.

Substitute into equation 2

v' =[ (0.025×220) +(2.25×0)+(0.025×110)]/2.25

v' = 3.67 m/s.

Hence the velocity of the watermelon = 3.67 m/s

7 0

4 years ago

What is the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high (formula:pe=mgh)

yKpoI14uk [10]

The potential energy of a 25 kg bicycle resting at the top of a hill 3 m high will be 735.75 J.

<h3>What is potential energy?</h3>

The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule.

The potential energy is mainly depending upon the height of the object. when the cyclist is at the highest position, the height is maximum. Therefore, the potential energy is also maximum.

The potential energy is found as;

PE=mgh

PE=25 kg× 9.81 m/s² ×3 m

PE= 735.75 J.

Hence, the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high will be 735.75 J.

To learn more about the potential energy, refer to the link;

brainly.com/question/24284560

#SPJ1

5 0

2 years ago

A hockey puck sliding along frictionless ice with speed v to the right collides with a horizontal spring and compresses it by 1.

patriot [66]

Answer:

The spring's maximum compression will be 2.0 cm

Explanation:

There are two energies in this problem, kinetic energy $K= \frac{mv^{2}}{2}$ and elastic potential energy $U= \frac{kx^{2}}{2}$ (with m the mass, v the velocity, x the compression and k the spring constant. ) so the total mechanical energy at every moment is the sum of the two energies:

$E=K+U$

Here we have a situation where the total mechanical energy of the system is conserved because there are no dissipative forces (there's no friction), so:

$E_{i}=E_{f}$

$K_{i}+U_{i}=K_{f}+U_{f}$

Note that at the initial moment where the hockey puck has not compressed the spring all the energy of the system is kinetic energy, but for a momentary stop all the energy of the system is potential elastic energy, so we have:

$K_{i} = U_{f}$

$\frac{mv^{2}}{2}=\frac{kx^{2}}{2}$ (1)

Due conservation of energy the equality (1) has to be maintained, so if we let k and m constant x has to increase the same as v to maintain the equality. Therefore, if we increase velocity to 2v we have to increase compression to 2x to conserve the equality. This is 2(1.0) = 2.0 cm

7 0

3 years ago

What is the molecular formula for the hydrocarbon in the mass spectrum above?

PtichkaEL [24]

What is the structure of a hydrocarbon that has $\mathrm{M}^{+}=120$ in its mass spectrum and has the following $1 \mathrm{H}$ NMR spectrum? 7.25 $\delta(5 \mathrm{H}, \text { broad singlet); } 2.90 \delta(1 \mathrm{H}, \text { septet, } J=7 \mathrm{Hz}) ; 1.22 \delta(6 \mathrm{H},\text { doublet, }$ $J=7 \mathrm{Hz})$

6 0

3 years ago