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8_murik_8 [283]
3 years ago
8

If the net external force acting on a system is zero , then the total momentum of the system is zero

Physics
2 answers:
Neporo4naja [7]3 years ago
8 0
If net external force acting on the system is zero, momentum is conserved. That means, initial and final momentum are same → total momentum of the system is zero.
antoniya [11.8K]3 years ago
8 0

Answer: FALSE

Explanation: Momentum is the product of the mass of an object and the velocity of that object,momentum is a vector quantity which means it has a Magnitude (distance covered) and Direction.

Force is the product of the mass of an object and its acceleration,Force can also be described as the weight of an object after the force of gravity acts on its mass.

If the net force acting on an object is zero it does not mean that the momentum of that system is zero, because momentum does not solely depends on forces,it has to do with the MASS of the object and the VELOCITY of the object.

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LenaWriter [7]

Answer:

The components of the moving frame is (8.07c, -2, 3, 9.493)

Solution:

As per the question:

Velocity of moving frame w.r.t original frame v_{m} 0.85c

Point 'a' of an event in one reference frame corresponds to the (x, y, z, t) coordinates of the plane

a = (0, - 2, 3, 5)

Now, according the the question, the coordinates of moving frame, say (X, Y, Z, t'):

New coordinates are given by:

X = \frac{x - v_{m}t}{\sqrt{1 - \frac{v_{m}^{2}}{c^{2}}}}

X = \frac{0 - 0.85c\times 5}{\sqrt{1 - \frac{(0.85c)^{2}}{c^{2}}}}

X = 8.07 c

Now,

Y = y = - 2

Z = z = 3

Now,

t' = \frac{t - \frac{vx}{c}^{2}}{\sqrt{1 - (\frac{v}{c})^{2}}}

t' = \frac{5 - 0}{\sqrt{1 - (\frac{0.85c}{c})^{2}}} = 9.493 s

4 0
3 years ago
Rebecca heated 50mL of water from 0 degrees Celsius to 60 degrees Celsius. How much energy did she use to heat the water? Rememb
GuDViN [60]

Answer:

Q = 12540  J

Explanation:

It is given that,

Mass of water, m = 50 mL = 50 g

It is heated from 0 degrees Celsius to 60 degrees Celsius.

We need to find the energy required to heat the water. The formula use to find it as follows :

Q=mc\Delta T

Where c is the specific heat of water, c = 4.18 J/g°C

Put all the values,

Q=50\times 4.18\times (60-0)\\Q=12540\ J

So, 12540 J of energy is used to heat the water.

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2 years ago
Jeffery gains super strength and pushes two different objects with the same amount of force. Object A accelerates at 40 m/s2, an
Montano1993 [528]

Answer: Object B

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3 years ago
Kepler’s third law can be used to derive the relation between the orbital period, P (measured in days), and the semimajor axis,
NikAS [45]
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P² = kA³
where
P = period, days
A = semimajor axis, AU
k = constant

Given:
P = 687 days
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Therefore
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Answer:  1.3439 x 10⁵ (days²/AU³)

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3 years ago
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