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8_murik_8 [283]
4 years ago
8

If the net external force acting on a system is zero , then the total momentum of the system is zero

Physics
2 answers:
Neporo4naja [7]4 years ago
8 0
If net external force acting on the system is zero, momentum is conserved. That means, initial and final momentum are same → total momentum of the system is zero.
antoniya [11.8K]4 years ago
8 0

Answer: FALSE

Explanation: Momentum is the product of the mass of an object and the velocity of that object,momentum is a vector quantity which means it has a Magnitude (distance covered) and Direction.

Force is the product of the mass of an object and its acceleration,Force can also be described as the weight of an object after the force of gravity acts on its mass.

If the net force acting on an object is zero it does not mean that the momentum of that system is zero, because momentum does not solely depends on forces,it has to do with the MASS of the object and the VELOCITY of the object.

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A long copper wire of radius 0.321 mm has a linear charge density of 0.100 μC/m. Find the electric field at a point 5.00 cm from
krek1111 [17]

Answer:

E=35921.96N/C

Explanation:

From the question we are told that:

Radius r=0.321mm

Charge Density \mu=0.100

Distance d= 5.00 cm

Generally the equation for electric field is mathematically given by

E=\frac{mu}{2\pi E_0r}

E=\frac{0.100*10^{-6}}{2*3.142*8.86*10^{-12}*5*10^{-2}}

E=35921.96N/C

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3 years ago
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Scrat [10]

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3 years ago
An electric heating element is connected to a 110v circuit and a current of 3.2 a is flowing through the element. How much energ
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2.580 Wh.... .........
7 0
3 years ago
Read 2 more answers
A ball is thrown from ground level so as to just clear wall 4m height at distance 4m from wall and falls 14 m from wall . Veloci
kolbaska11 [484]
Ok, this is a 2d kinematics problem,  the falls 14 m part is confusing, I think it means in the x direction, but you don't need it anyway.

If we know it goes 4m into the air, we know  d = 4m (height of wall), we also know the acceleration a=-9.8m/s^2 (because gravity) and that the vertical velocity when it just clears the wall will be 0 m/s, which we'll call our final velocity (Vf). Using Vf^2 = Vi^2 +2a*d, we can solve this for Vi and drop Vf because it's zero to get: Vi = sqrt(-2ad), plug in numbers (don't forget a is negative) and you get 8.85 m/s in the vertical direction. The x-direction velocity requires that we solve the y-direction for time, using Vf= Vi + at, we solve for t, getting t= -Vi/a, plug in numbers t= -8.85/-9.8 = 0.9 s. Now we can use the simple v = d/t (because x-direction has no acceleration (a=0)), and plug in the distance to the wall and the time it takes to get there v = (4/.9) = 4.444 m/s, this is the velocity in the x direction, we use Pythagoras' theorem to find the total velocity, Vtotal = sqrt(Vx^2 + Vy^2), so Vtotal = sqrt(8.85^2+4.444^2) = 9.9m/s. Yay physics!
8 0
3 years ago
A student wants to approximate the amount of work that the force due to gravity does on the student as the student walks up a se
Inessa [10]

Answer:

Options A and D

Explanation:

In this question the student needs to collect these measurements in order to approximate the work done

A. The mass of the student

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The vertical height has to be known as gravity only acts straight down.

3 0
3 years ago
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