Answer:
Magnetic field,
Explanation:
It is given that,
Speed of proton,
Mass of the proton,
Charge on proton,
We need to find the magnetic field strength required to just balance the weight of the proton and keep it moving horizontally.
The Lorentz force is given by :
.............(1)
The weight of proton,
..............(2)
From equation (1) and (2), we get :
Hence, this is the required solution.
Answer:
α = 5.75°
Explanation:
In this case, the problem states that both springs have identical lenghts and we also have theri constant. We want to know the angle of the rod with the horizontal. This can be found with the following expression:
sinα = Δx/L
α = sin⁻¹ (Δx/L) (1)
However, we do not have Δx. This can be found when half of the weight of the rod is balanced. In this way:
F₁ = k₁*x₁ ----> x₁ = F₁ / k₁ (2)
And the force is the weight in half so: F₁ = mg/2
Replacing in (2) we have:
x₁ = (1.3 * 9.8) / (2 * 58) = 0.1098 m
Doing the same thing with the other spring, we have:
x₂ = (1.3 * 9.8) / (2 * 36) = 0.1769 m
Now the difference will be Δx:
Δx = 0.1769 - 0.1098 = 0.0671 m
Finally, we can calculate the angle α, from (1):
α = sin⁻¹(0.0671 / 0.67)
<h2>
α = 5.75 °</h2>
Hope this helps
<span>A. 59 degrees......
Hope it works</span>
Answer: did you get the answers?
Explanation: