Use ideal gas law PV=nRT
at STP, pressure is 1atm and temperature is 273K (0 Celsius)
1×1.5L=n × 0.0821 × 273
n is moles and R is ideal gas law constant, always 0.0821
moles= 14.9422(6.02×10^23 molecules)=9.0×10^24 molecules
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The molarity of a solution is defined as the moles of solute dissolved per kilogram of solvent. Therefore, we first compute the moles of KOH using:
Moles = mass / Mr
Moles = 23 / 56
Moles = 0.41
The volume of solvent is 1.6 liters
The density is 1 gram/cm³ = 1 kg/L
Mass of solvent = density * volume
Mass of solvent = 1 * 1.6
Mass of solvent = 1.6 kg
Molality = moles / kilogram
Molarity = 0.41 / 1.6
Molarity = 0.26
The molality of the solution is 0.26 molal.
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