Question

A force of 150N at an angle of 60 degree to the horizontal to pull a box through a distance of 50m calculate the work done

Answer 1

• Force=150N
• Angle=60°
• Displacement=50m

$\boxed{\sf W=Fscos\Theta}$

$\\ \sf\longmapsto W=150(50)cos 60$

$\\ \sf\longmapsto W=7500\times \dfrac{1}{2}$

$\\ \sf\longmapsto W=3750J$