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andrew11 [14]
2 years ago
7

The light elastic rod supports a 4 kg sphere. when an 18n vertical force is applied to the sphere, the rod deflects 14 mm. a) fi

nd the amplitude and natural frequency of the system when the 18n force is suddenly released. b) if there is an earthquake and the wall oscillates with a harmonic frequency of 2 hz and an amplitude of 15 mm up and down, determine the amplitude of vibration for the sphere.
Physics
1 answer:
Zinaida [17]2 years ago
8 0

The amplitude of vibration for the sphere will be 29.48 nm.

<h3 /><h3>What is amplitude?</h3>

The distance between from the crest of a wave to the next crest is known as the amplitude.

The amplitude of the sphere is;

\rm A= \frac{\delta_0}{[1-(\frac{\omega}{\omega_n}^2]} \\\\

The stiffness of the load is;

\rm K = \frac{F}{\triangle y }\\\\ K=\frac{18}{0.014}  \\\\ K=1285.71 \ N/m

The natural frequency is;

\rm \omega_n= \sqrt{\frac{k}{m}} \\\\ \rm \omega_n= \sqrt{\frac{1285.71}{4}} \\\\ \omega_n=17.93 \ rad/sec

Put the obtained values in the amplitude formula;

\rm A= \frac{0.015}{[1-(\frac{4 \pi}{17.93}^2]} \\\\ A= 0.02948 \\\\ A= 29.48 \ nm

Hence,the amplitude of vibration for the sphere will be 29.48 nm.

To learn more about the amplitude, refer:

brainly.com/question/8662436

#SPJ1

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There is a seasaw that's holding two men. The seesaw has a length of 18m that can pivot from a point at its center. Man 1 has a
Alex

Answer:

Distance=  2.3864m

Explanation:

So that the balance is in equilibrium parallel to the floor, we must match the moment each man makes with respect to the pivot point.

In many cases the point of application of force does not coincide with the point of application in the body. In this case the force acts on the object and its structure at a certain distance, by means of an element that transfers that action of this force to the object.

This combination of force applied by the distance to the point of the structure where it is applied is called the moment of force F with respect to the point. The moment will attempt a rotation shift or rotation of the object. The distance from the force to the point of application is called the arm.

Mathematically it is calculated by expression:

M= F×d

The moment caused by the first man is:

M1= 75kg × (9.81m/s²) × 1.75m= 1287.5625 N×m

The moment caused by the second man must be equal to that caused by the first by which:

M2= 1287.5625 N×m= 55kg × (9.81m/s²) × distance ⇒

⇒distance= (1287.5625 N×m)/( (55kg × (9.81m/s²) )= 2.3864m

At this distance from the pivot point, the second should sit down so that the balance is balanced parallel to the ground.

3 0
3 years ago
¿Cuál es la magnitud y dirección de la aceleración de los cuerpos en caída libre en el planeta Tierra?
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6 0
3 years ago
While driving north at 25 m/s during a rainstorm you notice that the rain makes an angle of 38° with the vertical. While driving
Natali [406]

Answer:21.33^{\circ}

Explanation:

Given

velocity of driver v_1=25 m/s w.r.t ground towards north

driver observes that rain is making an angle of 38^{\circ} with vertical

While returning v_2=25 m/s w.r.t. ground towards south

suppose u_1=velocity of rain drop relative car while car is going towards north

u_2=velocity of rain drop relative car while car is going towards south

z=vector sum of u_1 & v_1

Now from graph

\tan 38=\frac{v_1+v_2}{u_2}

u_2=\frac{25+25}{\tan 38}=64 m/s

z=\vec{u_2}+\vec{v_2}

therefore magnitude of z is given by

|z|=\sqrt{u_2^2+v_2^2}

|z|=\sqrt{64^2+25^2}

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\tan A=\frac{v_2}{u_2}

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6 0
3 years ago
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Answer:

The right solution is "84.09 nm".

Explanation:

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Refractive index of oil (n),

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Now,

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= \frac{555}{4\times 1.65}

= \frac{555}{6.6}

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The bigger one as the luminosity has a direct exponential relationship with R of the star so the star which has more surface area will be more luminous than the smaller one
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