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Gre4nikov [31]
2 years ago
12

The first law of thermodynamics states that energy can neither be created nor destroyed. If this is true then why are we always

looking for new sources of energy? Use the 2nd law of thermodynamics to answer this question.
Physics
1 answer:
riadik2000 [5.3K]2 years ago
5 0

Answer:

The second law of thermodynamics states in an isolated system, the entropy (the amount of thermal energy that cannot be converted into mechanical work, also known as the amount of disorder) always increases, therefore, an isolated system always require an external input (new sources) of energy for there to be orderliness or for the available energy of the system to remain constant or increase

Explanation:

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How high can a 40 N force move a load, when 395 J of work is done?
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Answer:

9.875

Explanation:

w=f×s

395=40×s

make s the subject of the formula

s=395/40

=9.875

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Many biological systems are well-described by the laws of statistical physics. A simple yet often powerful approach is to think
GuDViN [60]

Answer:

z1/z2

Explanation:

we have no quantum effects therefore we can make use of Maxwell Boltzmann distribution in the description of this system.

using the boltzman distribution the probability of finding a particle in energy state

P_{ei}  = \frac{gie^{-ei/kol} }{z}

we have

gi to be degeneration of the ith state

ei to be energy of ith state

z=e^{-ei/kbt} summation

P_{ope} = \frac{e^{-ei/kBt} }{z} = \frac{Z_{1} }{Z}

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8 0
3 years ago
Consider a container of oxygen gas at a temperature of 23°C that is 1.00 m tall. Compare the gravitational potential energy of a
Sergio039 [100]

Answer:

Yes, it is reasonable to neglect it.

Explanation:

Hello,

In this case, a single molecule of oxygen weights 32 g (diatomic oxygen) thus, the mass of kilograms is (consider Avogadro's number):

m=1molec*\frac{1mol}{6.022x10^{23}molec} *\frac{32g}{1mol}*\frac{1kg}{1000g}=5.31x10^{-26}kg

After that, we compute the potential energy 1.00 m above the reference point:

U=mhg=5.31x10^{-26}kg*1.00m*9.8\frac{m}{s^2}=5.2x10^{-25}J

Then, we compute the average kinetic energy at the specified temperature:

K=\frac{3}{2}\frac{R}{Na}T

Whereas N_A stands for the Avogadro's number for which we have:

K=\frac{3}{2} \frac{8.314\frac{J}{mol*K}}{6.022x10^{23}/mol}*(23+273)K\\ \\K=6.13x10^{-21}J

In such a way, since the average kinetic energy energy is about 12000 times higher than the potential energy, it turns out reasonable to neglect the potential energy.

Regards.

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3 years ago
What is the net force acting on the piano
CaHeK987 [17]

answer: 500 net force

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