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Ostrovityanka [42]
3 years ago
9

If the refractive index of a medium is 1.3,

Physics
2 answers:
Nataly [62]3 years ago
3 0

Explanation:

see the above attachment to solve the question and get the answer.

hope this helps you.

Lena [83]3 years ago
3 0

Answer:

We know that refractive index of medium is n=

speedoflightinvacuum

speedoflightinvaccum

n=

v

c

,

c is the velocity of light in vacuum and v is velocity in that medium.

For water :

n=

v

c

1.3=

2.25×10

8

c

c=2.925×10

8

m/s

For glass :

c=2.925×10

8

m/s

n

glass

=

v

glass

c

1.5=

v

glass

2.925×10

8

v

glass

=1.95×10

8

m/s

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A gymnast of mass 62.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t
MrRissso [65]

Answer:

a) T = 608.22 N

b) T = 608.22 N

c) T = 682.62 N

d) T = 533.82 N

Explanation:

Given that the mass of gymnast is m = 62.0 kg

Acceleration due to gravity is g = 9.81 m/s²

Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.

So;

To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;

T = mg

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs the rope at a constant rate tension in the string is

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs up the rope with an upward acceleration of magnitude

a = 1.2 m/s²

the tension in the string is  T - mg = ma (Since acceleration a is upwards)

T = ma + mg

= m (a + g )

= (62.0 kg)(9.81 m/s² + 1.2  m/s²)

= (62.0 kg) (11.01 m/s²)

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When the gymnast climbs up the rope with an downward acceleration of magnitude

a = 1.2 m/s² the tension in the string is  mg - T = ma (Since acceleration a is downwards)

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5 0
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Harman [31]

PV=nRT

Here

P=Pressure

V=Volume

n=Molarity

R=universal gas constant

T=Temperature.

LHS

\\ \tt\bull\leadsto PV

\\ \tt\bull\leadsto [ML^2T^{-2}][M^0L^3T^0]

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RHS

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hence verified

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