Directly vertical. The surface area is the smallest, allowing for the water upthrust to be kept to a minimum, whilst the mass is the same, which keeps the same weight and gravitational pull.
Answer: Change in velocity: -10 m/s, acceleration=-2.5m/s
Explanation:
The question in english is written below:
The end of a robotic arm moves to the right at 8m s. Four seconds later it moves to the left at 2m/s. What is its change in velocity and what is its change in acceleration?
We have the following data:
Initial Velocity of the robotic arm: (to the right)
Final Velocity of the robotic arm: (to the left)
Variation in time:
Firstly we have to calculate the change in velocity , which is given by the following equation:
This means the resultant velocity is to the left
Now, we can find the acceleration , given by:
This means the acceleration is also to the left, however its magnitude is always positive:
Answer: 17939.74 yards
Explanation:
Given , A rectangular measures 100 meters by 150 meters
To find : Area of rectangle.
Formula :
Area of rectangle = Length x width
Here, let length = 100 meters and width = 150 meters
Then, Area of rectangle = 100 meters x 150 meters = 15,000 square meters
Also , 1 meter = 1.09361 yards
Then, Area of rectangle = 15,000 x 1.09361 x 1.09361 square yards
= 17939.7424815 square yards
≈ 17939.74 yards
Hence, the area of rectangle is 17939.74 yards .
In answering this problem, you have to know the concepts behind Newton's Laws of Motion. When a coin is tossed up in the air, the only force acting upon it is the force of gravity. It is the force pulling the object towards the center of the Earth. This acceleration, according to Newton's 2nd Law of Motion, produces a constant acceleration equal to 9.81 m/s². This is an empirical data that is specific only to circumstances on Earth.
Part a. From the starting point, you exert a force so it speeds up with an initial velocity. As it goes up, the velocity decreases because the force of gravity is constantly pulling it down. The coin will eventually reach a maximum height, where its velocity will reach zero. Afterwhich, the velocity increases again as it goes back down to the ground. The motion is now faster because it is parallel and in the same direction of the gravitational force.
Part b. As mentioned earlier, the acceleration is constant because the force of gravity is always acting upon an object. Whether it goes up and returns back down, the acceleration will always be of the same value.