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Helen [10]
3 years ago
9

A student conducts an experiment to determine how the temperature of water affects the time for sugar to dissolve. In each trial

, the
student uses a different amount of water and a different temperature of water.
What is wrong with this experimental design?
Chemistry
1 answer:
V125BC [204]3 years ago
8 0

The fact that the student used different amount of water (another independent variable) is wrong with the experimental design

WHAT ARE THE COMPONENTS OF AN EXPERIMENT?

  • An experiment aims at solving a scientific problem or answering a scientific question. An experiment should contain a variable being changed called INDEPENDENT VARIABLE and a variable being measured called DEPENDENT VARIABLE.

  • In an ideal experiment, only one independent variable should be used while every other variable should be kept constant. This is done so as not to affect the result of the experiment.

In the experiment conducted by the student in this question, two independent variables were used i.e. the different amount of water and the different temperatures. This is what is wrong about the experimental design.

  • In a nutshell, the fact that two independent variables were used by the student is what is wrong about the experimental design.

Learn more at: brainly.com/question/967776

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Explanation:

Greenhouse gases are gases in Earth's atmosphere that trap heat. They let sunlight pass through the atmosphere, but they prevent the heat that the sunlight brings from leaving the atmosphere.

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What happens in nuclear fission?
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Splitting an atoms nucleus apart
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A sample of carbon dioxide gas is reduced to 1/3 of its original volume while the pressure is observed to doubleplaced in a cont
masya89 [10]

Answer:

The temperature will change and become 2/3 of its original.

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given ,  

The volume of the sample gets reduced 1/3 of the original. So,

V₂ = 1/3V₁

The pressure of the sample is doubled of the original. So,

P₂ = 2P₁

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac {{P_1}\times {V_1}}{T_1}=\frac {{2\times P_1}\times {\frac{1}{3}\times V_1}}{T_2}

T_2=\frac{2}{3}\times T_1

<u>The temperature will change and become 2/3 of its original.</u>

5 0
3 years ago
How are energy and work related? A. Energy is the force needed to do work B. Work times energy is force C. Energy is the capacit
Svetllana [295]

Answer:

I believe the answer is A

Explanation:

Work and energy are related because when you work, you cause displacement in the object you are exerting upon. While this happens, you transfer energy between the systems. Both work and energy share the same SI unit, called the joule.

4 0
3 years ago
Read 2 more answers
According to the molecular orbital energy-level diagram below, which one of the following statements is not correct about NO, NO
Lubov Fominskaja [6]

None of the statement is not correct about NO, NO+, and NO−.

Explanation:

Those molecules whose all subshells are completely filled are diamagnetic.

Those molecules whose any sub-shell is incomplete is termed paramagnetic.

Let us check the magnetism in all three molecules based on molecular orbital theory and Lewis structure

NO= number of electrons 11

It form N=O having configuration 1s2,2s2,2p6,3s1, it has 1 unpaired electron so it is paramagnetic.

Now NO-, number of electrons 12 having configuration 1s2,2s2,2p6,3s2, no unpaired electron hence dimagnetic.

Now NO+, number of electrons is 10 having configuration 1s2,2s2,2p6,3s2, dimagnetic

Let us calculate the bond order of NO-

N0- have 12 electrons as 5 of nitrogen, 6 of oxygen and 1 of - charge on oxygen.

So, bond order = \frac{8-4}{2}

                          = 2 double bonds

bond order of NO+, Number of electrons is 10

bond order= \frac{8-2}{2}

bond order = 3

bond order of NO, number of electrons 11

bond order= \frac{8-3}{2}

bond order=2.5

Larger the bond order shorter the bond.

4 0
4 years ago
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