How many moles of Na3PO4 would be required to react with 1.0 mol of AgNO3?
2 answers:
<u>Answer:</u> The number of moles of sodium phosphate required is 0.33 moles
<u>Explanation:</u>
We are given:
Moles of silver nitrate = 1 mole
The chemical equation for the reaction of sodium phosphate and silver nitrate follows:
By Stoichiometry of the reaction:
3 moles of silver nitrate reacts with 1 mole of sodium phosphate.
So, 1.0 moles of silver nitrate will react with = of sodium phosphate.
Hence, the number of moles of sodium phosphate required is 0.33 moles
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Answer:
The volume of the gas will be 78.31 L at 1.7 °C.
Explanation:
We can find the temperature of the gas by the ideal gas law equation:
Where:
n: is the number of moles
V: is the volume
T: is the temperature
R: is the gas constant = 0.082 L*atm/(K*mol)
From the initial we can find the number of moles:
Now, we can find the temperature with the final conditions:
The temperature in Celsius is:
Therefore, the volume of the gas will be 78.31 L at 1.7 °C.
I hope it helps you!