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iragen [17]
3 years ago
14

4. A salvage operator recovered coins believed to be gold. A sample weighed 385.000g and has a volume of 20.0mL. Were the coins

gold (Density= 19.3g/mL) or yellow brass (Density =8.47g/mL)? Show your calculation and explain your answer.
Chemistry
1 answer:
aleksley [76]3 years ago
5 0

Answer:

Gold

Explanation:

We are given that

Mass of sample ,m=385 g

Volume ,V=20mL

We have to find the coin is gold or yellow brass.

We know that

Density=\frac{Mass}{volume}

Using the formula

Density=\frac{385}{20}g/mL

Density=19.25g/mL

Density\approx 19.3g/mL

Density of coin=19.3g/mL

Density of gold=19.3g/mL

Hence, the coin is gold.

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3 years ago
Based on the equation, how many grams of Br2 are required to react completely with 36.2 grams of AlCl3?
s2008m [1.1K]

Answer:

65.08 g.

Explanation:

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<em>2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,</em>

2.0 mole of AlCl₃ reacts with 3.0 mole of Br₂ to produce 2.0 mole of AlBr₃ and 3.0 mole of Cl₂.

  • Firstly, we need to calculate the no. of moles of 36.2 grams of AlCl₃:

<em>n = mass/molar mass</em> = (36.2 g)/(133.34 g/mol) = <em>0.2715 mol.</em>

<u><em>Using cross multiplication:</em></u>

2.0 mole of AlCl₃ reacts with → 3.0 mole of Br₂, from the stichiometry.

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