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2 years ago

Is it difficult or easy to obtain hydro power

Chemistry

1 answer:

Paha777 [63]2 years ago

3 0

Answer:yes

Explanation:

cause yes

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On the periodic table, in which period is copper?

Firdavs [7]

Answer:

At the top of Group 11 above silver and gold.

Period 4

Explanation:

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3 years ago

Please someone help me Balance this equation.

NeTakaya

Answer: This is an oxidation-reduction (redox) reaction:

3 C-II - 12 e- → 3 CII (oxidation)

4 CrVI + 12 e- → 4 CrIII (reduction)

C2H5OH is a reducing agent, K2Cr2O7 is an oxidizing agent.

7 0

3 years ago

Study the following unbalanced half-reaction. Which equation represents the balanced half-reaction? H2O2 ---> H2O

Aleonysh [2.5K]

O: 1*2 = 2*1
H 2 + 2 = 2*2 

answer C hope you get it right

5 0

3 years ago

Read 2 more answers

At a given temperature, 4.06 atm of H2 and 3.5 atm of Cl2 are mixed and allowed to come to equilibrium. The equilibrium pressure

Llana [10]

Answer: The value of $K_p$ for the given chemical reaction is 0.1415

Explanation:

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of the products and the reactants each raised to the power their stoichiometric ratios. It is expressed as $K_p$

For a general chemical reaction:

$aA+bB\rightarrow cC+dD$

The expression for $K_p$ is written as:

$K_p=\frac{p_{C}^cp_{D}^d}{p_{A}^ap_{B}^b}$

For the given chemical equation:

$H_2(g)+Cl_2(g)\rightleftharpoons 2HCl(g)$

The expression for $K_p$ for the following equation is:

$K_p=\frac{(p_{HCl})^2}{(p_{H_2)}(p_{Cl_2})}$

We are given:

$p_{HCl}=1.418atm\\p_{H_2}=4.06atm\\p_{Cl_2}=3.5atm$

Putting values in above equation, we get:

$K_p=\frac{(1.418)^2}{(4.06)\times (3.5)}\\\\K_p=0.1415$

The value of $K_p$ for the given chemical reaction is 0.1415

5 0

3 years ago

When sulfuric acid and potassium hydroxide neutralize each other to make water and potassium sulfate, how is water formed?

statuscvo [17]

It's formed by the hydrogen ion of the acid and the hydroxide of the base.

$H_{2} SO_{4} + 2KOH --\ \textgreater \ K_{2} SO_{4} + 2H_{2}O$
Sulfuric Acid + potassium superoxide --> Potassium Sulfate + Heavy Water

Hope this Helps :)

3 0

4 years ago