Mechanical Energy
Mechanism energy is the energy associated with the position and motion of an object. Therefore it is also the summation of the kinetic and potential energies of the object.
Explanation:
Mechanism energy is the energy associated with the position and motion of an object. Therefore it is also the summation of the kinetic and potential energies of the object.
In the muscles, to have movement, the chemical bonds in ATP is broken to enable the sliding action of the myosin and actin fibres of a sarcomere (the basic unit of muscle). This sliding action is responsible for contraction of muscle. The coordinated contractions and relaxations of sarcomeres on muscles result in movement which translates to mechanical energy.
This process is never 100% efficient with some energy lost as heat energy.
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Answer:
M₂ = 0.0745 M
Explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = 0.0952 M
V₁ = 38.73 mL
M₂ = ?
V₂ = 49.48 mL
Using the above formula , the molarity of ammonia , can be calculated as ,
M₁V₁ = M₂V₂
0.0952 M * 38.73 mL = M₂* 49.48 mL
M₂ = 0.0745 M
Depending on how the design is, The bridge will sway, bounce, or move in some way. If the bridge was too stiff the winds would destroy the bridge and cause it to crumble and fall.
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Answer:
pH = 9.48
Explanation:
We have first to realize that NH₃ is a weak base:
NH₃ + H₂O ⇔ NH₄⁺ + OH⁻ Kb = 1.8 x 10⁻⁵
and we are adding this weak base to a solution of NH₄NO₃ which being a salt dissociates 100 % in water.
Effectively what we have here is a buffer of a weak base and its conjugate acid. Therefore, we need the Henderson-Hasselbach formula for weak bases given by:
pOH = pKb + log ( [ conjugate acid ] / [ weak base ]
mol NH₃ = 0.139 L x 0.39 M = 0.054 mol
mol NH₄⁺ = 0.169 L x 0.19 M = 0.032 mol
Now we have all the information required to calculate the pOH ( Note that we dont have to calculate the concentrations since in the formula they are a ratio and the volume will cancel out)
pOH = -log(1.8 x 10⁻⁵) + log ( 0.032/0.054) = 4.52
pOH + pH = 14 ⇒ pH = 14 - 4.52 = 9.48
The solution is basic which agrees with NH₃ being a weak base.
