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4 years ago

What is 20/7 as a mixed number

2 answers:

8 0

20/7 as a mixed number is 2 6/7
9/4 as a mixed number is 2 1/4
22/5 as a mixed number is 4 2/5
4/3 as a mixed number is 1 1/3

Olin [163]4 years ago

6 0

$\frac{20}{7}=2 \frac{6}{7} \\ 
 \\ \frac{9}{4}=2 \frac{1}{4} \\ 
 \\ \frac{22}{5}=4 \frac{2}{5} \\ 
 \\ \frac{4}{3}=1 \frac{1}{3} \\$

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valentina_108 [34]

Answer:

Step-by-step explanation:

Substitute the given numbers for the variables.

-(-2)(6-3)2

2(3)2

6 0

4 years ago

Does anyone know this??

STALIN [3.7K]

Hi there! The answer is C.

Explanation:
We have the following equation:

$\frac{8}{15} = \frac{x}{6}$
To solve this type of equation (with an x in the denominator of a fraction) we must cross-multiply the numerator and the denominator.

$15 \times x = 8 \times 6$
Multiply

$15x = 40$
Divide both sides by 15.

$x = \frac{40}{15} = 2 \frac{2}{3}$
~ Hope this helps you!

5 0

3 years ago

Read 2 more answers

The sales of lawn mowers t years after a particular model is introduced is given by the function y = 5500 ln(9t + 4), where y is

Nimfa-mama [501]

Given:

The function is:

$y=5500\ln (9t+4)$

Where y is the sales of lawn mowers t years after a particular model is introduced.

To find:

How many mowers will be sold 3 years after a model is introduced?

Solution:

We have,

$y=5500\ln (9t+4)$

Substituting $t=3$ , we get

$y=5500\ln (9(3)+4)$

$y=5500\ln (27+4)$

$y=5500\ln (31)$

On substituting the approximate value of ln(31), we get

$y=5500\times 3.433987$

$y=18886.9285$

$y\approx 18887$

Therefore, the 18887 mowers will be sold 3 years after a model is introduced.

6 0

3 years ago

Simplify write in scientific notation 0.5(8x10^5)

Oksi-84 [34.3K]

10 to the 5th power means 5 times zero, place 8 before that and it will be 800000 then multiply with 0.5 it will be 400000. In scientific notation it will be like 4x10 the 5th power.

7 0

3 years ago

Read 2 more answers

What is the value of log 256/ log 1024

Scrat [10]

Answer:

0.8

Step-by-step explanation:

The change of base formula for logarithms can be used to find this value exactly. (Your calculator can also tell you.)

$\log_b(a)=\dfrac{\log(a)}{\log(b)}$

Using this relation with the given numbers, we have ...

$\dfrac{\log(256)}{\log(1024)}=\dfrac{\log(2^8)}{\log(2^{10})}=\dfrac{8\cdot\log(2)}{10\cdot\log(2)}=\dfrac{8}{10}\\\\\boxed{\dfrac{\log(256)}{\log(1024)}=0.8}$

3 0

2 years ago