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4 years ago

What is 20/7 as a mixed number

2 answers:

8 0

20/7 as a mixed number is 2 6/7
9/4 as a mixed number is 2 1/4
22/5 as a mixed number is 4 2/5
4/3 as a mixed number is 1 1/3

Olin [163]4 years ago

6 0

$\frac{20}{7}=2 \frac{6}{7} \\ 
 \\ \frac{9}{4}=2 \frac{1}{4} \\ 
 \\ \frac{22}{5}=4 \frac{2}{5} \\ 
 \\ \frac{4}{3}=1 \frac{1}{3} \\$

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Amy’s grandmother is exactly 6 times older than Amy.

aev [14]

Answer:

i think it is 5 in not sure hope this had helped

Step-by-step explanation:

7 0

4 years ago

Will be giving brainliest to whoever can answer this question

Step2247 [10]

Answer:

see below

Step-by-step explanation:

360 - 56 - 106 = 198 degrees

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8 0

3 years ago

How do you solve for x/3 - x/5

ch4aika [34]

Answer:

x/3 - x/5 = 2/15x

Step-by-step explanation:

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3 years ago

35 solve the following syste

blondinia [14]

Part A: The solution is $(-0.923,5.692)$

Part B: The point $(3,7)$ is not in the solution set.

Explanation:

Part A: The given inequalities are $3 x+4 y>20$ and $x$

The solution can be determined by solving the two inequalities by substitution method.

Changing inequalities to equality, we have,

$x=3 y-18$ and $3 x+4 y=20$

Let us substitute $x=3 y-18$ in the equation $3 x+4 y=20$ , we get,

$3 (3y-18)+4 y=20$

$9y-54+4y=20$

$13y=74$

$y=5.692$

Substituting $y=5.692$ in $x=3 y-18$ , we get,

$x=3 (5.692)-18$

$=17.076-18$

$x=-0.923$

Thus, the solution set is $(-0.923,5.692)$

Part B: Now, we shall determine whether the point $(3,7)$ is in the solution set.

Let us substitute the point $(3,7)$ in the inequalities $3 x+4 y>20$ and $x$ , we get,

$3 (3)+4 (7)>20$

$9+28>20$

$37>20$

Also, substituting $(3,7)$ in $x$ , we get,

$3$

Since, the point $(3,7)$ does not satisfy one of the inequality $x$ , the solution set does not contain the point $(3,7)$

Thus, the point $(3,7)$ is not in the solution set.

8 0

3 years ago

Help could you explain step by step?

mel-nik [20]

Answer:

x = 2 , y = 11

Step-by-step explanation:

the diagonals of a parallelogram bisect each other , then

PT = TR , that is

y = 5x + 1 → (1)

QT = TS , that is

2y = 6x + 10 → (2)

substitute y = 5x + 1 into (2)

2(5x + 1) = 6x + 10

10x + 2 = 6x + 10 ( subtract 6x from both sides )

4x + 2 = 10 ( subtract 2 from both sides )

4x = 8 ( divide both sides by 4 )

x = 2

substitute x = 2 into either of the 2 equations for corresponding value of y

substituting into (1)

y = 5(2) + 1 = 10 + 1 = 11

6 0

2 years ago

Read 2 more answers