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3 years ago

What is 20/7 as a mixed number

2 answers:

8 0

20/7 as a mixed number is 2 6/7
9/4 as a mixed number is 2 1/4
22/5 as a mixed number is 4 2/5
4/3 as a mixed number is 1 1/3

Olin [163]3 years ago

6 0

$\frac{20}{7}=2 \frac{6}{7} \\ 
 \\ \frac{9}{4}=2 \frac{1}{4} \\ 
 \\ \frac{22}{5}=4 \frac{2}{5} \\ 
 \\ \frac{4}{3}=1 \frac{1}{3} \\$

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The scores on a test are normally distributed with a mean of 110 and a standard deviation of 22. What is the score that is 3 sta

Alborosie

Answer:

Step-by-step explanation:

If the mean is 110, and the standard devaition is 22,

1 standard dev. below the mean is 110-22

2 standard dev below the mean is 110-22-22

3 standard dev below the mean is 110-22-22-22

Hope that helps!

7 0

3 years ago

Compare 7/12 and 1/2

Klio2033 [76]

7/12 and 1/2
Get the common denominator
Multiply 1/2 by 6
7/12 and 6/12

3 0

3 years ago

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Sixteen-twentyfive as a decimals

olga_2 [115]

16.25 or .1625 is the awsner

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2 years ago

The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle

Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

$|AB|=\sqrt{(-1--5)^2+(8-6)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

The length of AD is

$|AD|=\sqrt{(-1--5)^2+(6-4)^2}$

$|AD|=\sqrt{16+4}$

$|AD|=\sqrt{20}$

The length of BC is:

$|BC|=\sqrt{(-1-3)^2+(8-6)^2}$

$|BC|=\sqrt{16+4}$

$|BC|=\sqrt{20}$

The length of CD is

$|CD|=\sqrt{(-1-3)^2+(6-4)^2}$

$|CD|=\sqrt{16+4}$

$|CD|=\sqrt{20}$

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB $=\frac{8-6}{-1--5}=\frac{1}{2}$

Slope of BC $=\frac{8-6}{-1-3}=-\frac{1}{2}$

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus

7 0

2 years ago

Read 2 more answers

If a TV has 200 ft by 875 ft what is the total mass of it

mafiozo [28]

There's no way to find the mass with the information given.
"200 ft" and "875 ft" are linear dimensions ... things you would
measure with a ruler. They tell us how long or wide or high the
TV is. None of that information tells us anything about its mass.

By the way ... those are gigantic measurements. I was working
in Wrigley Field here in Chicago just before opening day in 2015,
when the new video screens were being installed. I saw them
up close while the cranes lifted them into position. None of the
Chicago Cubs' new screens is as big as the numbers in the question,
and I'm pretty sure the whole score-board isn't that big either.
Something is definitely wrong here.

8 0

3 years ago

Read 2 more answers