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I am Lyosha [343]
3 years ago
12

Josh did an experiment recording the changes in temperature in sand and water when exposed to a light source, and then when the

light source was removed. Josh noticed that the sand heated up faster than the water and then cools faster than the water. Josh concludes that
Physics
2 answers:
Marrrta [24]3 years ago
7 0

Before going to solve this question first we have to understand specific heat capacity of a substance .

The specific heat of a substance is defined as amount of heat required to raise the temperature of 1 gram of substance through one degree Celsius. Let us consider a substance whose mass is m.Let Q amount of heat is given to it as a result of which its temperature is raised  from T to T'.

Hence specific heat  of a substance is calculated as-

                                              c= \frac{Q}{m[T'-T]}

Here c is the specific heat capacity.

The substance whose specific heat capacity is more will take more time to be heated up to a certain temperature as compared to a substance having low specific heat which is to be heated up to the same temperature.

As per the question John is experimenting on sand and water.Between sand and water,water has the specific heat 1 cal/gram per degree centigrade which is larger as compared to sand.Hence sand will be heated faster as compared to water.The substance which is heated faster will also cools faster.

From this experiment John concludes that water has more specific heat as compared to sand.

frozen [14]3 years ago
3 0

Answer:

we can conclude that emissivity of sand will me more than the emissivity of water

Explanation:

As we know that here Source of light is the energy source from which energy is continuously incident on the Sand and Water

So here we know that rate of energy incident on sand and water will be from same source at same rate

Here this energy absorbed by the system is given as

\frac{dQ}{dt} = \sigma e A(T^4 - T_s^2)

so here the rate of energy absorbed is more sand than water

Also when source is off than rate of energy dissipated by sand is more than the water

So here we can conclude that emissivity of sand will me more than the emissivity of water

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In creating his definition of horsepower, James Watt, the inventor of the steam engine, calculated the power output of a horse o
Studentka2010 [4]

Answer:

Part a)

F = 182.3 Lb

Part b)

P = 0.55 HP

Explanation:

Diameter of the circle = 24 ft

Diameter = 731.52 cm = 7.3152 m

now the horse complete 144 trips in one hour

so time to complete one trip is given as

t = \frac{3600}{144} s

t = 25 s

now the speed of the horse is given as

v = \frac{2\pi r}{t}

v = \frac{\pi(7.3152)}{25}

v = 0.92 m/s

Part a)

Now we know that the power is defined as rate of work done

it is given as

P = F v

746 = F(0.92)

F = 810.9 N

F = 182.3 Lb

Part b)

Work done to climb up to 3 m height is given by

W = mgh

now we have

Power = \frac{Work}{time}

P = \frac{mgh}{t}

P = \frac{(70kg)(9.81)(3)}{5.0s}

P = 412.02 Watt

now we know that 1 HP = 746 Watt

so we have

P = \frac{412}{746} = 0.55 HP

8 0
3 years ago
An object weighs 79.1 N in air. When it is suspended from a force scale and completely immersed in water the scale reads 21.8 N.
Free_Kalibri [48]

Answer:

(a). The density of the object is 1382 kg/m³.

(b). The density of the oil is 536.4 kg/m³.

Explanation:

Given that,

Weight in air = 79.1 N

Weight in water = 21.8 N

Weight in oil = 48.4 N

We need to calculate the volume of object

Using formula of buoyant force

F_{b}=W_{air}=W_{water}

F_{b}=79.1-21.8

F_{b}=57.3\ N

F_{b}=\rho g h

Put the value into the formula

57.3=1000\times V\times 9.8

V=\dfrac{57.3}{1000\times9.8}

V=5.84\times10^{-3}\ m^3

We need to calculate the density

Using formula of buoyant force

F_{b}=\rho Vg

79.1=\rho\times5.84\times10^{-3}\times9.8

\rho=\dfrac{79.1}{5.84\times10^{-3}\times9.8}

\rho=1382\ kg/m^3

The density of the object is 1382 kg/m³.

(b). We need to calculate the volume of object

Using formula of buoyant force

F_{b}=W_{air}=W_{oil}

F_{b}=79.1-48.4

F_{b}=30.7\ N

We need to calculate the density

Using formula of buoyant force

F_{b}=\rho_{oil} Vg

30.7=\rho_{oil}\times5.84\times10^{-3}\times9.8

\rho_{oil}=\dfrac{30.7}{5.84\times10^{-3}\times9.8}

\rho=536.4\ kg/m^3

The density of the oil is 536.4 kg/m³.

Hence, This is the required solution.

4 0
4 years ago
5. The rate at which an organism uses energy, measured in humans at complete<br> rest.
yuradex [85]

Answer:

n. Abbr. BMR. The rate at which energy is used by an organism at complete rest, measured in humans by the heat given off per unit time, and expressed as the calories released per kilogram of body weight or per square meter of body surface per hour.

Explanation:

3 0
3 years ago
Atoms can be "cooled" to incredibly low temperatures by letting them interact with a laser beam. Various novel quantum phenomena
Oksanka [162]

Answer:

the rms speed of cesium atoms that have been cooled to a temperature of 100nK = 0.43cm/s or 0.0043m/s

Explanation:

The concept of root mean square velocity is applied, where the average translational kinetic is related to the actual kinetic energy, the expression for the root mean square is the generated.

The detailed steps and appropriate substitution is as shown in the attachment.

8 0
3 years ago
I WILL GIVE BRAINLIEST HELP DUE TODAY!!!
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Mechanical digestion begins in the mouth as the food is chewed.(it prepares the food for chemical digestion) Chemical digestion involves breaking down the food into simpler nutrients that can be used by the cells. Chemical digestion begins in the mouth when food mixes with saliva. Saliva contains an enzyme (amylase) that begins the breakdown of carbohydrates.
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3 years ago
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