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I am Lyosha [343]
3 years ago
12

Josh did an experiment recording the changes in temperature in sand and water when exposed to a light source, and then when the

light source was removed. Josh noticed that the sand heated up faster than the water and then cools faster than the water. Josh concludes that
Physics
2 answers:
Marrrta [24]3 years ago
7 0

Before going to solve this question first we have to understand specific heat capacity of a substance .

The specific heat of a substance is defined as amount of heat required to raise the temperature of 1 gram of substance through one degree Celsius. Let us consider a substance whose mass is m.Let Q amount of heat is given to it as a result of which its temperature is raised  from T to T'.

Hence specific heat  of a substance is calculated as-

                                              c= \frac{Q}{m[T'-T]}

Here c is the specific heat capacity.

The substance whose specific heat capacity is more will take more time to be heated up to a certain temperature as compared to a substance having low specific heat which is to be heated up to the same temperature.

As per the question John is experimenting on sand and water.Between sand and water,water has the specific heat 1 cal/gram per degree centigrade which is larger as compared to sand.Hence sand will be heated faster as compared to water.The substance which is heated faster will also cools faster.

From this experiment John concludes that water has more specific heat as compared to sand.

frozen [14]3 years ago
3 0

Answer:

we can conclude that emissivity of sand will me more than the emissivity of water

Explanation:

As we know that here Source of light is the energy source from which energy is continuously incident on the Sand and Water

So here we know that rate of energy incident on sand and water will be from same source at same rate

Here this energy absorbed by the system is given as

\frac{dQ}{dt} = \sigma e A(T^4 - T_s^2)

so here the rate of energy absorbed is more sand than water

Also when source is off than rate of energy dissipated by sand is more than the water

So here we can conclude that emissivity of sand will me more than the emissivity of water

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Using energy considerations, calculate the average force (in N) a 62.0 kg sprinter exerts backward on the track to accelerate fr
slava [35]

Answer:

69.68 N

Explanation:

Work done is equal to change in kinetic energy

W = ΔK = Kf - Ki = \frac{1}{2} mv^{2} _{f}  - \frac{1}{2} mv^{2} _{i}

W = F_{total} .d

where m = mass of the sprinter

vf = final velocity

vi = initial velocity

W  = workdone

kf = final kinetic energy

ki = initial kinetic energy

d = distance traveled

Ftotal = total force

vf = 8m/s

vi= 2m/s

d = 25m

m = 60kg

inserting parameters to get:

W = ΔK = Kf - Ki = \frac{1}{2} mv^{2} _{f}  - \frac{1}{2} mv^{2} _{i}

F_{total} .d =\frac{1}{2} mv^{2} _{f}  - \frac{1}{2} mv^{2} _{i}

F_{total} = \frac{\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}}{d}

F_{total=} \frac{\frac{1}{2} X 62 X6^{2} -\frac{1}{2} X 62 X2^{2} }{25}

= 39.7

we know that the force the sprinter exerted F sprinter, the force of the headwind Fwind = 30N

F_{sprinter} = F_{total} + F_{wind}  = 39.7 + 30 = 69.68 N

7 0
3 years ago
Read 2 more answers
A car traveling at 34 m/s runs out of gas while traveling up a 5.0 â slope. how far will it coast before starting to roll back d
g100num [7]
Angle = 5°
Acceleration = a = g x Sin(θ) where g = 9.8m/s² <span>= 9.8*Sin(6) = 0.854 m/s</span>²<span> , <span>

As coasting comes to a stop: 

v = a x t = 0 

t = v/a = 34/0.854 = 39.8 seconds 

The distance traveled is: 

d = (vf-vi)t - (1/2)at</span></span>²<span><span> = 34 x 39.8 - (1/2)(0.854)(39.8)</span></span>²<span><span> = 1353.2 -676.4
</span></span> <span>= 676.8 m</span>
5 0
4 years ago
The fastest pitched baseball was clocked at 47 m/s. Assume that the pitcher exerted his force (assumed to be horizontal and cons
Eduardwww [97]

Answer:

Following are the solution to the given points:

Explanation:

For point a:

Find the schematic of the empty body and in attachment. Upon on ball during the pitch only two forces act:

The strength of the pitcher F is applied that operates horizontally. Its gravity force acting on an object is termed weight, which value is where m denotes mass, and g the acceleration of gravity.

For point b:

160.2\  N

First, they must find that ball's acceleration. You can use the SUVAT equation to achieve that

where

v = 47\  \frac{m}{s} \\\\u = 0 \\\\a =?\\\\d = 1.0 \ m \\\\

Solving for a,

a=\frac{v^2-u^2}{2d}=\frac{47^2-0}{2(1.0)}=1104.5 \ \frac{m}{s^2}

Calculating the mass:

m = 145 g = 0.145 kg

Calculating the force:

F=ma=0.145 \times 1104.5= 160.2 \ N

 For point c:

0.195 times the pitcher's weight

m = 84 \ kg \\\\g = 9.8\ \frac{m}{s^2}\\\\

Solving for W:

W=84 \times 9.8= 823.2 \ N

Now the force of Part B could be defined as the fraction of the mass of the pitcher:  

\frac{F}{W}=\frac{160.2}{823.3}=0.195

4 0
3 years ago
A long uniform board weighs 52.8 N (10.6 lbs) rests on a support at its mid point. Two children weighing 206.0 N (41.2 lbs) and
balandron [24]

The upward force exerted on the board by the support is mathematically given as

Fu= 764.8 N

<h3>What is the upward force exerted on the board by the support?</h3>

Generally, the equation for is  mathematically given as

Considering that the Net Force on the system is null

The weight of the children plus the weight of the board equals the upward force imposed on the support.

The upward force

Fu= 440 + 272 + 52.8 N

Fu= 764.8 N

In conclusion, he upward force exerted on the board by the support

Fu= 764.8 N

Read more about force

brainly.com/question/13191643

#SPJ1

8 0
2 years ago
Hehe i hate being a single girl....what physical properties dose europium have
sasho [114]

Answer:

Europium has a bright shiny surface. it's steel grey and has a melting point of 826 degree Celsius and a boiling point of about 1,489 degree Celsius.

Explanation:

the density is 5.24 grams per cubic centimeter.

3 0
3 years ago
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