Answer:
9.07 L
Explanation:
<em>Calculate the volume occupied at s.t.p by 6.89 g of NH₃ gas [H = 1.0, N = 14.0].</em>
Step 1: Given and required data
- Molar mass of NH₃ (M): 17.0 g/mol
Step 2: Calculate the moles (n) of NH₃
We will use the following epxression.
n = m / M
n = 6.89 g / (17.0 g/mol) = 0.405 mol
Step 3: Calculate the volume occupied by 0.405 moles of NH₃ at STP
At STP, 1 mole of NH₃ occupies 22.4 L (assuming ideal behavior).
0.405 mol × 22.4 L/1 mol = 9.07 L
Explanation:
A proton and an electron have an equal amount but an opposite type of charge. Thus, if an atom contains equal numbers of protons and electrons, the atom is described as being electrically neutral.
The heat required by the cube of iron has been 602.64 J.
The specific heat has been given as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.
The heat required has been expressed as:
<h3 /><h3>Computation for the heat required by Iron sample</h3>
The mass of the sample has been given as 55.8 g
The specific heat of tin has been, 
The change in temperature, (
) has been:
Substituting the values for the heat required:
The heat required by the cube of iron has been 602.64 J.
Learn more about specific heat, here:
brainly.com/question/26217572
Answer:
They both classify as halogens they are both in the fluorine family and their both in group 17 on the periodic table
Explanation:
That's all I could come up with
