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kirill115 [55]
3 years ago
12

Which equation is equivalent to the formula below?

Mathematics
2 answers:
agasfer [191]3 years ago
7 0
Option c is right………..
Trava [24]3 years ago
6 0

Answer:

option C is best.

Step-by-step explanation:

y=a(x-h)^2+k

y-k=a(x-h)^2y

y-k/(x-h)^2=a

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Please solve for x and is it complementary or supplementary
Viktor [21]
The answer is 10 x and i think complementary but i could be wrong so you may want someone else to answer that
5 0
3 years ago
8.
Tpy6a [65]

Area of the shaded region = area of big square minus area of little square.

Here is the set up:

Let A_s = area of shaded region.

A_s = (2x + 2)(3x - 4) - [(x - 3)(x - 6)]

Take it from here.

3 0
2 years ago
Read 2 more answers
Jake ate 4/8 of a pizza. Millie ate 3/8 of the same pizza. How much of the pizza was eaten by jake and Millie?
Alexus [3.1K]
I believe they both had 7/8
3 0
3 years ago
Do the values in the table represent a proportional relationship?
Marianna [84]

Answer:

NOT proportional

Step-by-step explanation:

y/x  = 5/2 = 2.5

y/x = 6/3 = 2

also 7/4 = 1. 75 and 8/5 = 1.6  so:-

They are NOT proportional

5 0
3 years ago
World population is approximately upper p equals 6.4 left-parenthesis 1.0126 right-parenthesis superscript t, with upper p in bi
Leviafan [203]

Given equation is

P=6.4(1.0126)^t

It gives approx world population in billions for t years since 2004.


Answer(a):

Compare with growth formula P=a(b)^t, we get:

growth factor b = 1.0126

We know that if r is the percent rate of growth then

1+r=b

1+r=1.0126

r=0.0126

Hence the yearly percent rate of growth of the world population is 0.0126 or 1.26%.


Answer(b):

To find worlds population in 2004, plug t=0 because year is counted from 2004.

P=6.4(1.0126)^0 = 6.4*1 = 6.40

Hence answer is 6.40 billion.


To find worlds population in 2018, plug t=2018-2004=14 because year is counted from 2004.

P=6.4(1.0126)^{14} = 6.4*1.19160117479 = 7.62624751867

Hence answer is approx 7.63 billion.


Answer(c):

Average rate of change of the world population between 2004 and 2018 is given by:

\frac{P\left(Year_{2018}\right)-P\left(year_{2004}\right)}{2018-2004}

=\frac{P\left(14\right)-P\left(0\right)}{14-0}

=\frac{7.63-6.40}{14}

=0.0878571428571

Hence answer is approx 0.0878571428571 billion per year.

To convert it into millions, multiply by 1000

So we get 0.0878571428571*1000 = 87.8571428571

Which is approx 88 to the nearest integer

Hence final answer is approx 88 millions per year.

7 0
3 years ago
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