Solution :
int f(int x){
;
}*/
int f(
){
int stack[2] = {
};
;
;
;
R1 = R1 * C; /*R1 = 
*/
;
* R2; /* R0 = bx */
; /*R0 = 
*/
;
; /*R0 = a+bx+cx^2 */
![\text{R1 = stack[0];}](https://tex.z-dn.net/?f=%5Ctext%7BR1%20%3D%20stack%5B0%5D%3B%7D)
![\text{ R2 = stack[1];}](https://tex.z-dn.net/?f=%5Ctext%7B%20R2%20%3D%20stack%5B1%5D%3B%7D)
}
/*
int s=0;
{ 
;)
*/
AREA SumSquares, code, readWrite
ENTRY
;loop 
MOV r1, #0 ; s = 0
Loop 
;calculate i*i
;s = s+ i*i
, #1 ; i = i+1
,#10 ; test for end
Loop ; 
END
Instead of having to write multiple pieces of code for different outcomes, you can use an elseif statement and make your code easier to read and easier to understand.
Answer:
Binary file.
Explanation:
In this case, the network security analyst is using the Follow TCP Stream feature in Wireshark to rebuild the TCP transaction. However, the transaction data seems indecipherable. The explanation for this is that the TCP transaction file is a Binary File and because of this the network secuirty analyst is unable to decipher the transaction file.
The solution for this is to convert the binary file into text file which is human readable.
Answer:B
Explanation:Showing parts of a whole.
Answer: 1000 square ponds of force hope you know the answer
Explanation: i guessed
