The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
Answer:
with what do u need help with?
Answer:
she raked 11 bags of leaves
Step-by-step explanation:
24.75 divided by 2.25= 11
Answer:
Solution set {x|x<8}
Step-by-step explanation:
0.35x - 4.8<5.2- 0.9x
0.35x+0.9x<5.2+4.8
1.25x<10
x<10/1.25
x<8
Solution set {x|x<8}
Answer would be 58.5 yd^2 .
You should take the base of the triangle multiplied by the height.
Formula: 1/2×base×height
In this case, you know that base is 13yd and height is 9 yd.
So, apply the formula.
Area = 1/2(13yd)(9yd) = 58.5 yd^2
*Do not include the " invisible length as it is not part of the actual triangle.
*Do not include 32yd as it is a hypotenuse and not a base. Hypotenuse is a side that is opposite a right angle triangle.
