The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
X = 20
Isolate the variable by dividing each side by factors that don't contain the variable.
x
=
20
400 lbs = 0.2 tons
38,600 mg = 3.86 dekagrams
Hope it helps!
Answer:
The answer is x = 4
Step-by-step explanation:
1. First you need to distribute the 3/4 * (x + 8). This looks like (3/4) * (x) + (3/4) * (8) = 9
2. Next you simplify the distributed equation, 3/4x + 6 = 9
3. Now subtract 6 from both sides, 3/4x = 3
4. Multiply both sides by 4/3, 4/x * 3/4x = 3 * 4/3
5. Simplify, x = 4
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