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yawa3891 [41]
3 years ago
8

A 16 g piece of Styrofoam carries a net charge of -8.6 µC and floats above the center of a large horizontal sheet of plastic tha

t has a uniform charge density on its surface. What is the charge per unit area on the plastic sheet?
Physics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

the charge per unit area on the plastic sheet is - 3.23 x 10⁻⁷ C/m²

Explanation:

given information:

styrofoam mass, m = 16 g = 0.016 kg

net charge, q = - 8.6 μC

to calculate the charge per unit area on the plastic sheet, we can use the following equation:

F_{e} = mg

where

F_{e} = the force between the electric field

m = mass

g = gravitational force

F_{e} =qE

where

q = charge

E = electric field

and

E = σ/2ε₀

where

ε₀ = permitivity

thus

F_{e} =qE

mg = qσ/2ε₀

σ = (2mg ε₀)/q

  = 2 (0.016) (9.8)  (8.85 x 10⁻¹²)/( - 8.6 x 10⁻⁶)

  = - 3.23 x 10⁻⁷ C/m²

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3. A moving<br> car covers a distance of 100 km in two hours.<br> What is meant by this?
GenaCL600 [577]

Answer:

50km /hour

Explanation:

The car moves 100km in two hours.

We can write a ratio like this:

100km : 2hr

Divide both sides by two and you get:

50km : 1hr

Meaning the moving car is moving 50km an hour.

Hope this helps :)

8 0
3 years ago
A space station consists of two donut-shaped living chambers, A and B, that have the radii shown in the drawing. As the station
tensa zangetsu [6.8K]
The angle subtended by the arc of movement of both chambers is the same. Thus:
S = r∅, for chamber A:

2.3 x 10² = 3.2 x 10² ∅
∅ = 0.72 rad

∅ is the same for B so:
S = 1.1 x 10³ x 0.72
S = 7.92 x 10² m
6 0
3 years ago
Spymaster Paul, flying a constant 215km/h horizontally in a low-flying helicopter, want to drop secret documents into his contac
aleksandrvk [35]

Answer:

\theta = 49.56 degree

Explanation:

Relative horizontal velocity of plane with respect to the car is given as

v_r = v_p - v_c

so we have

v_p = 215 km/h

v_c = 155 km/h

now we have

v_r = 215 - 155

v_r = 60 km/h

v_r = 16.67 m/s

Now time taken by the object to drop the vertical height is given as

y = \frac{1}{2}gt^2

78 = \frac{1}{2}(9.81)t^2

t = 3.98 s

so the distance of the car must be

d = v_r\times t

d = 16.67 \times 3.98

d = 66.47 m

Angle of the car with horizontal is given as

tan\theta = \frac{y}{x}

tan\theta = \frac{78}{66.47}

\theta = tan^{-1}(1.17)

\theta = 49.56 degree

5 0
3 years ago
For the meter stick shown in figure 10-4, the force F1 10.0 N acts at 10.0 cm. What is the magnitude of torque due to F1 about a
Phantasy [73]

Torque is equal position vector times (r) times force vector (F).  Since F= 10 N and r = 0.1 m, so the torque is equal to (10 N) x ( 0.1 m) = 1Nm. The direction of the torque would be into the screen, clockwise rotation.

8 0
3 years ago
Despite a vigorous training schedule and careful meal planning, Anthony “hit the wall” at mile 12 of his half-marathon and he ha
Lorico [155]

Answer:

Condition of fatigue caused by depletion of glycogen

Explanation:

Let us examine how a body produces energy. There are two ways:

Fat metabolism

Fatty acids in the body help to capture adenosine triphosphate (ATP) which produces energy. On a per gram basis fatty acids yields the most ATP when oxidized completely.

Glycogen breakdown

the enzyme glycogen phosphorylase cleaves glycogen from the non reducing ends to produce monomers of glucose-1-phosphate. These monomers are used by the human body to supply energy.

When a person is exercising his/her VO₂ i.e., the oxygen consumption reaches maximum, here most of the energy comes from glycogen. While exercising most of the energy comes from glycogen breakdown.

So, when Anthony hit the wall it means that he has depleted his source of glycogen and can no longer produce glucose which provides him energy.

5 0
3 years ago
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