The airplane refuels between City A and continues on to City B. It travels at an average speed of 733.9 km/h. If the trip takes
1 answer:
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Answer:
F = 789 Newton
Explanation:
Given that,
Speed of the car, v = 10 m/s
Radius of circular path, r = 30 m
Mass of the passenger, m = 60 kg
To find :
The normal force exerted by the seat of the car when the it is at the bottom of the depression.
Solution,
Normal force acting on the car at the bottom of the depression is the sum of centripetal force and its weight.
N = 788.6 Newton
N = 789 Newton
So, the normal force exerted by the seat of the car is 789 Newton.
Answer:
Part(a): The value of the spring constant is .
Part(b): The work done by the variable force that stretches the collagen is .
Explanation:
Part(a):
If '' be the force constant and if due the application of a force '
' on the collagen '
' be it's increase in length, then from Hook's law
Also, Young's modulus of a material is given by
where '' is the area of the material and '
' is the length.
Comparing equation () and (
) we can write
Here, we have to consider only the circular surface of the collagen as force is applied only perpendicular to this surface.
Substituting the given values in equation (), we have
Part(b):
We know the amount of work done () on the collagen is stored as a potential energy (
) within it. Now, the amount of work done by the variable force that stretches the collagen can be written as
Substituting all the values, we can write