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Rus_ich [418]
3 years ago
8

A point source at the origin emits sound of frequency 175 Hz uniformly in all directions. On the x-axis at x=100 m, the sound in

tensity is 1.40 * 10^-4 W/m^2 . 1. What is the power output of the source?
2. What is the intensity ( in SI units ) on the x-axis at x=160m?
3. What is the intensity in decibels on the x-axis at x=160m? 4. A steady wind is blowing at 5.00 m/s in the positive x-direction. An observe on a bicycle at x=200 m is moving along the x-axis in the negative direction ( i.e., towards the source of sound ) at a speed of 12.0 m/s. What frequency of sound does the cyclist hear?
Physics
1 answer:
hammer [34]3 years ago
8 0

Answer:

Multiple answers:

1. Power output P=17.59W

2.Intensity 160m I=17.6W/m^{2}

3. dB = 77.3

4. f=178.5 Hz

Explanation:

First one comes from the expression

I=\frac{P}{4\pi r^{2} }

where<em> I </em>is the intensity, <em>P </em>is the power and <em>r </em>is the radio of the spherical wave, or in this case, the distance <em>x</em>. I solved for the Power by multiplying Intensity with the area (4\pi x^{2}

Second one is done with:

\frac{I_{2} }{I_{1} } =\frac{x^{2}_{1} }{x^{2} _{2}}

Solving for Intensity 2, the result mentioned.

The third is simply computed with

dB=10*log\frac{I}{10^{-12} }

And finally the last one is done with doppler effect, taking into account the speed of the air as in 10ºC 337m/s.

f=f_{initial} *(\frac{s+v_{receiver} }{s+v_{source} } )

Where <em>Finitial</em> is the frequency emitted and <em>s</em> is the speed of the sound. The wind blowing in positive is, in principle, going away of the observer.

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