A solution has an absorbance of 0.2 with a path length of 1 cm. Given the molar absorptivity coefficient is 59 cm⁻¹ M⁻¹, the molarity is 0.003 M.
<h3>What does Beer-Lambert law state?</h3>
The Beer-Lambert law states that for a given material sample, path length and concentration of the sample are directly proportional to the absorbance of the light.
A solution has an absorbance of 0.2 with a path length of 1 cm. Given the molar absorptivity coefficient is 59 cm⁻¹ M⁻¹, we can calculate the molarity of the solution using the following expression.
A = ε × b × c
c = A / ε × b
c = 0.2 / (59 cm⁻¹ M⁻¹) × 1 cm = 0.003 M
where,
- A is the absorbance.
- ε is the path length.
- b is the molar absorptivity coefficient.
- c is the molar concentration.
A solution has an absorbance of 0.2 with a path length of 1 cm. Given the molar absorptivity coefficient is 59 cm⁻¹ M⁻¹, the molarity is 0.003 M.
Learn more about the Beer-Lambert law here: brainly.com/question/12975133
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Answer: 0.002 M
Explanation:
The balanced chemical equation for ionization of 
in water is:
According to stoichiometry :
1 mole of ionizes to give =2 mole of 
ions
0.001 mole of ionizes to give = 
mole of ions
Thus of a solution of 0.001 M aqueous sulfuric acid is 0.002 M
Answer:
The equilibrium shifts to produce more reactants.
Explanation:
According to the Le- Chatelier principle,
At equilibrium state when stress is applied to the system, the system will behave in such a way to nullify the stress.
The equilibrium can be disturb,
By changing the concentration
By changing the volume
By changing the pressure
By changing the temperature
Consider the following chemical reaction.
Chemical reaction:
2SO₂ + O₂ ⇄ 2SO₃
In this reaction the equilibrium is disturb by increasing the concentration of Product.
When the concentration of product is increased the system will proceed in backward direction in order to regain the equilibrium. Because when product concentration is high it means reaction is not on equilibrium state. As the concentration of SO₃ increased the reaction proceed in backward direction to regain the equilibrium state and more reactant is formed.
