Answer:
The Aluminium sample
Explanation:
From the question,
ΔQ of the iron = Cm(t₂-t₁)........................ Equation 1
Given: C = specific heat capacity of iron, m = mass of iron, t₁ and t₂ = initial and final temperature respectively.
Given: m = 175 g = 0.175 kg, t₂ = 21.5°C, t₁ = 99.7°C
Constant: C = 444 J/kgK.
Substitute into equation 1
ΔQ = 0.175(444)(21.5-99.7)
ΔQ = -6076.14 J
Similarly, for aluminium,
ΔQ' = c'm'(t₂-t₁)...................... Equation 2
Given: m' = 175 g = 0.175 kg,
Constant: 900 J/kgK
ΔQ' = 0.175(900)(21.5-99.7)
ΔQ' = -12316.5 J
Hence the aluminium sample undergoes the greater heat change
Answer:
A is an endothermic reaction.
Explanation:
When energy of breaking bonds is greater than the energy released during making of bonds, we need to supply energy to the reaction and thus the reaction is called as endothermic reaction. We can also say that the enthalpy of formation of products is more than the enthalpy of formation of reactants making overall enthalpy change to be positive.
While in case B, the energy to break bond is less than the energy released during making of bonds. thus there is overall released of energy during the reaction and hence it is exothermic reaction.
Answer:
The value of the equilibrium constant 
at this temperature is 3.42.
Explanation:
Partial pressure of the sulfur dioxide =
Partial pressure of the oxygen gas =
Partial pressure of the sulfur trioxide =
The expression of an equilibrium constant is given by :
The value of the equilibrium constant at this temperature is 3.42.
