All categories

3 years ago

Explain why arginine is a basic amino acid

Chemistry

2 answers:

svlad2 [7]3 years ago

8 0

Answer :

arginine is basic amino acid because it's side chain group contains a full positive charge at the physiological pH. Histidine is also considered basic but it can have a positive or a neutral charge on its side chain group at the physiological pH

please mark me Brainliest

Mumz [18]3 years ago

3 0

Answer:

There are three amino acids that have basic side chains at neutral pH. These are arginine (Arg), lysine (Lys), and histidine (His). Their side chains contain nitrogen and resemble ammonia, which is a base. Their pKa's are high enough that they tend to bind protons, gaining a positive charge in the process.

<h2>Hope it helps you.</h2>

You might be interested in

Which element of weather is caused by a difference in air pressure between two air masses?

cestrela7 [59]

Wind results due to difference in air pressure of air masses. Due to difference in pressure of two air masses, low pressure zone is created by lifting of one the air mass above the other as the movement of air takes place from higher pressure area to lower pressure area. This causes different wind speed in different areas. The direction of wind depends on its origin for example, a northerly wind always moves from north to south direction.

8 0

3 years ago

Read 2 more answers

Upper C upper O subscript 2 (g) plus upper H subscript 2 (g) right arrow Upper C upper O (g) plus upper H subscript 2 upper O (l

Dominik [7]

Hydrogen gas

Explanation:

Expression:

CO₂ + H₂ → CO + H₂O

Hydrogen gas in this reaction is oxidized in the reaction.

In this manner, it is the reducing agent in the reaction.

A reducing agent is the specie in a chemical reaction that undergoes the process of oxidation.

It is marked by:

Addition of oxygen to a specie
Removal of hydrogen from a specie
Loss of electron by an atom
Increase in oxidation number
Increase in number of electronegative atoms surrounding a specie.

Here we see that H₂ fits this criteria perfectly well.

CO₂ is the one reduced.

learn more:

Oxidizing agent brainly.com/question/5558762

#learnwithBrainly

8 0

4 years ago

Read 2 more answers

Which statement applies to electronegativity?

densk [106]

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

Electronegativity is defined as the tendency of an atom to attract the shared pair of electrons towards itself whenever a bond is formed.

This property increases as we move from left to right across a period because the number of charge on the nucleus gets increased and electrons are attracted more towards the nucleus.

This property decreases as we move from top to bottom in a group because the electrons get add up in the new shells which make them further away from the nucleus.

Thus, the correct answer is Option A.

7 0

3 years ago

Since a solution of KBr would probably cause significant damage to the car radiator and engine, you decide to use 125 g of the n

Vilka [71]

Answer:

When octane is used, the solution will have less effect on the freezing point depression of the solution

Explanation:

The complete question is:

Calculate the freezing point of a solution of 125 g KBr in 450 g water.

Since a solution of KBr would probably cause significant damage to the car radiator and engine, you decide to use 125 g of the nonelectrolyte octane (molar mass 114 g/mole). Will this have a greater or less effect on freezing point depression of the solution?

Step 1: Data given

Molar mass of KBr = 119.0 g/mol

Molar mass of octane = 114 g/mol

Mass of KBr = 125 grams

Mass of octane = 125 grams

Mass of water = 450 grams

Step 2: Calculate moles KBr

Moles KBr = mass KBr / molar mass KBr

Moles KBr = 125 grams / 119.0 g/mol

Moles KBr = 1.05 moles

Step 3: Calculate moles octane

Moles octane = 125 grams / 114 g/mol

Moles octane = 1.10 moles

Step 4: Calculate molality

Molality = moles compound / mass water

Molality KBr = 1.05 moles / 0.450 kg

Molality KBr = 2.33 molal

Molality octane = 1.10 moles / 0.450 kg

Molality octane = 2.44 molal

Step 5: Calculate the freezing point depression when KBr is used

ΔT = i*Kf * m

⇒with ΔT = the freezing point depression = TO BE DETERMINED

⇒with i = the van't Hoff factor of KBr = 2

⇒with Kf = the freezing point depression constant of water = 1.86 °C/m

⇒with m= the molality = 2.33 molal

ΔT = 2*1.86 * 2.33

ΔT = 8.68 °C

This means the freezing point of this solution is -8.68 °C

Step 6: Calculate the freezing point depression when octane is used

ΔT = i*Kf * m

⇒with ΔT = the freezing point depression = TO BE DETERMINED

⇒with i = the van't Hoff factor of the nonelectrolyte octane = 1

⇒with Kf = the freezing point depression constant of water = 1.86 °C/m

⇒with m= the molality = 2.44 molal

ΔT = 1* 1.86 * 2.44

ΔT = 4.54 °C

This means the freezing point of this solutions is -4.54 °C

When octane is used, the solution will have less effect on the freezing point depression of the solution

7 0

3 years ago

Select the sentences in the paragraph that explain only the dark lines that are produced in the absorption spectra. Select all t

Nady [450]

Answer:

Gaps are produced in the light spectra that correspond to wavelengths of absorbed photons.

Explanation:

When electrons in atoms absorb energy, they move from a lower energy level to a higher energy level. With time, they revert to the their original energy state emitting a photon of light of appropriate wavelength.

The absorbed photons do not show up in the spectrum. They appear as dark lines in the spectrum. Hence, the absorption spectrum is the exact inverse of the emission spectrum. The dark lines in the spectrum indicates that the colors that ought to occupied those points there have been absorbed.

5 0

3 years ago