Complete Question:
A machinist turns the power on to a grinding wheel, which is at rest at time t = 0.00 s. The wheel accelerates uniformly for 10 s and reaches the operating angular velocity of 25 rad/s. The wheel is run at that angular velocity for 37 s and then power is shut off. The wheel decelerates uniformly at 1.5 rads/s2 until the wheel stops. In this situation, the time interval of angular deceleration (slowing down) is closest to
Answer:
t= 16.7 sec.
Explanation:
As we are told that the wheel is accelerating uniformly, we can apply the definition of angular acceleration to its value:
γ = (ωf -ω₀) / t
If the wheel was at rest at t-= 0.00 s, the angular acceleration is given by the following equation:
γ = ωf / t = 25 rad/sec / 10 sec = 2.5 rad/sec².
When the power is shut off, as the deceleration is uniform, we can apply the same equation as above, with ωf = 0, and ω₀ = 25 rad/sec, and γ = -1.5 rad/sec, as follows:
γ= (ωf-ω₀) /Δt⇒Δt = (0-25 rad/sec) / (-1.5 rad/sec²) = 16.7 sec
Answer:
The work done to lift the counterweight equals the potential energy acquired
Explanation:
since this is vertically applied force on the counterweight, and the distance the force is displacing the counterweight is in the same direction as the applied force, it equals the gained potential energy
Answer:
149,700,000 km (= 1.50 x 10⁸ km)
Explanation:
Given,
Speed of light, c = 300,000 km/s
Time Taken = 8 min 19 s = 499 seconds
Recall, Distance = Speed x Time
= 300,000 km/s x 499 s
= 149,700,000 km
= 1.50 x 10⁸ km
This reaction, known as nuclear fusion, converts hydrogen atoms into helium. The by-product of nuclear fusion in theSun's core is a massive volume ofenergy that gets released and radiates outward toward the surface of the Sunand then into the solar system beyond it.
just reword it
Ptotal=Ptotal —> m1v1+m2v2=m1v1’+m2v2’ —> (1kg)(2m/s)+(1kg)(0m/s)=(1kg)(-1m/s)+(1kg)(v2’) —> v2’=3m/s
answer: v=3m/s
