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Wewaii [24]
3 years ago
6

A beam of electrons is sent horizontally down the axis of a tube to strike a fluorescent screen at the end of the tube. On the w

ay, the electrons encounter a magnetic field directed vertically downward. The spot on the screen will therefore be deflected: 1. not at all 2. upward 3. to the right as seen from the electron source 4. to the left as seen from the electron source 5. downward
Physics
1 answer:
slamgirl [31]3 years ago
4 0

Answer:

The answer is 3.

Explanation:

The answer to this question can be found by applying the right hand rule for which the pointer finger is in the direction of the electron movement, the thumb is pointing in the direction of the magnetic field, so the effect that this will have on the electrons is the direction that the middle finger points in which is right in this example.

So as a result of the magnetic field directed vertically downwards which is at a right angle with the electron beams, the electrons will move to the right and the spot will be deflected to the right of the screen when looking from the electron source.

I hope this answer helps.

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Whats the difference between kinetic and potential energy?
damaskus [11]
Kinetic energy is energy in motion and potential energy is stored energy
5 0
3 years ago
Where is the majority of the mass located in an atom
bogdanovich [222]
It's located in the nucleus
7 0
3 years ago
Two parallel plates 19 cm on a side are given equal and opposite charges of magnitude 2.0 ✕ 10^−9 C. The plates are 1.8 mm apart
Romashka [77]

Answer:

E   = 5291.00 N/C

Explanation:

Expression for capacitance is

C = \frac{\epsilon  A}{d}

where

A is area of square plate

D = DISTANCE BETWEEN THE PLATE

C = \frac{\epsilon\times(19\times 10^{-2})^2}{1.5\times 10^{-3}}

C = 24.06 \epsilon

C = 24.06\times 8.854\times 10^{-12} F

C =2.1\times 10^{-10} F

We know that capacitrnce and charge is related as

V = \frac{Q}{C}

 = \frac{2\tiimes 10^{-9}}{2.\times 10^{-10}}

v = 9.523 V

Electric field is given as

E = \frac{V}{d}

   = \frac{9.52}{1.8*10^{-3}}

E   = 5291.00 V/m

E   = 5291.00 N/C

5 0
2 years ago
The age of the universe is around 100,000,000,000,000,000s. A top quark has a lifetime of roughly 0.000000000000000000000001s. W
Maslowich

Answer:

10⁴¹ s quark top lives have been in the history of the universe.

Explanation:

You need to determine how many quark top lives there have been in the history of the universe, that is, what is the age of the universe divided by the lifetime of a top quark. Expressed in a formula, this is:

t\frac{Age of the universe}{Lifetime of a top quark}

Yo know that the "Age of the universe" is 100,000,000,000,000,000  which can also be expressed as 10¹⁷ s .

You also know that the "Lifetime of a top quark" is 0.000000000000000000000001 which can also be expressed as 10⁻²⁴ s.

Then t=\frac{10^{17} }{10^{-24} }

Recalling that the result of dividing two powers of the same base is another power with the same base where the exponent is the subtraction of the initial exponents, it is possible to calculate this division as follows:

t=10^{17-(-24)}

t=10^{17+24}

<u><em>t=10⁴¹ s</em></u>

So <u><em>10⁴¹ s quark top lives have been in the history of the universe.</em></u>

5 0
3 years ago
Can you be a teen at the age of 12
mr Goodwill [35]

Answer:

12 is a tween (preteen) and still growing, definitely still a kid and not really a teen

4 0
2 years ago
Read 2 more answers
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