Answer:
θ = (7π / 3) rad
Explanation:
given,
displacement of simple harmonic motion along x-axis
equation is given as
x = 5 sin (π t + π/3 )
general equation of simple harmonic motion
x = A sin θ
θ is the phase angle
θ = π t + π/3
at t = 2 s
Phase of the motion at t =2 s is θ = (7π / 3) rad
Answer:
work done in the process is 0 J.
Explanation:
Given :
Initial pressure of system ,
Final pressure of system ,
Volume of system ,
We know, In thermodynamics work done is defined as :
Here , P is pressure and is change in volume.
Now, coming back to question , it state that the process is isochoric .
Therefore, change in volume ,
Putting value of in above equation we get ,
W = 0 J.
Therefore , work done in this process is 0 J.
Hence, this is the required solution.