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3 years ago

Which type of force will an object move towards?

Physics

2 answers:

Makovka662 [10]3 years ago

4 0

Answer:

i think it's weakest

EDIT: It's net. I answered weakest but it was wrong and the correct answer was net. oops

Explanation:

if a strong force is acting on something it will push it away, meaning the object would go towards the weaker force

FromTheMoon [43]3 years ago

3 0

An object will move towards the strongest force.

Answer: Option B

Explanation:

Based on Newton's first law, an object will remain in its rest state or motion unless an some external forces act on it. The external force can be a balanced or unbalanced force.

The balanced forces act on an object with equal magnitudes but in opposite direction, so the net force will be zero. But unbalanced forces are the forces where the net forces on the object is not zero.

The best example for this is tug of war. Here, the tug will go towards the team who will pull with greater magnitude of force. Thus, the object will move towards the direction of strongest force among all on the unbalanced forces acting on the object.

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You adjust the temperature so that a sound wave travels more quickly through the air. You increase the temperature from 30 degre

katen-ka-za [31]

To calculate the velocity of the sound wave, we use this formula:
V = 331 + [0.6*T],
Where V is the velocity and T represents temperature.
When the temperature is 36 degree Celsius, we have
V = 331 + [0.6 * 36]
V = 331 + 21.6 = 352.6
Therefore, V = 352.6 m/s.

7 0

3 years ago

Read 2 more answers

A 0.001kg bullet is fired with a velocity of 800m/s into a soft wood of mass 1kg resting on a smooth surface. Find the final vel

V125BC [204]

The final velocity of the bullet+block is 0.799 m/s

Explanation:

We can solve this problem by applying the principle of conservation of momentum: in fact, the total momentum of the bullet-block system must be conserved before and after the collision.

Mathematically, we can write:

$mu+MU=(m+M)v$

where

m = 0.001 kg is the mass of the bullet

u = 800 m/s is the initial velocity of the bullet

M = 1 kg is the mass of the block

U = 0 is the initial velocity of the block (initially at rest)

v is the final combined velocity of the bullet and the block

Solving the equation for v, we find the final velocity:

$v=\frac{mu}{m+M}=\frac{(0.001)(800)}{0.001+1}=0.799 m/s$

Learn more about conservation of momentum:

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#LearnwithBrainly

4 0

3 years ago

What do you need to make 100 minutes charges neutral

Maru [420]

Neutrons are neutral and do not have any charge at all. Protons carry a positive charge, and electrons carry the negative charge.

4 0

3 years ago

Standing at a crosswalk, you hear a frequency of 530 Hz from the siren of an approaching ambulance. After the ambulance passes,

malfutka [58]

Answer:

_s = 37.77 m / s

Explanation:

This is an exercise of the Doppler effect that the change in the frequency of the sound due to the relative speed of the source and the observer, in this case the observer is still and the source is the one that moves closer to the observer, for which relation that describes the process is

f ’= f₀ $\frac{v}{v - v_s}$

where d ’= 530 Make

when the ambulance passes away from the observer the relationship is

f ’’ = f₀ $\frac{v}{v + v_s}$

where d ’’ = 424 beam

let's write the two expressions

f ’ (v-v_s) = fo v

f ’’ (v + v_s) = fo v

let's solve the system, subtract the two equations

v (f ’- f’ ’) - v_s (f’ + f ’’) = 0

v_s = v $\frac{ f' - f''}{ f' + f''}$

the speed of sound is v = 340 m / s

let's calculate

v_s = 340 $(\frac{ 530 -424}{530+424} )$

v_s = 340 $(\frac{106}{954}$ )

v_s = 37.77 m / s

5 0

3 years ago

Suppose you adjust your garden hose nozzle for a hard stream of water. you point the nozzle vertically upward at a height of 1.5

Lisa [10]

For problems especially pertaining motion, it is best to illustrate the problem to help you understand the problem. The picture I've attached is my illustration based on what I understood from the problem. Suppose the diamond in the picture is the nozzle. It is placed 1.5 m above the ground (bold horizontal line). The water coming out of the nozzle follows the direction of the arrows until it falls to the ground next to you holding the nozzle. When you turn it off, the water at the topmost part slowly comes back to the ground in 1.8 seconds.

Unfortunately, you weren't able to complete the problem. However, I would make a smart guess. I think it is logical that the problem would ask how high did the water shoot upwards from the nozzle, denoted as x. In order to solve this, we use the equations for free-falling objects:

t = √2h/g
1.8 = √2h/9.81
h = 15.9 m

To find the height of the water from the nozzle, we subtract the total height to 1.5 m to determine x.

x = 15.9 - 1.5 = 14.4 m

7 0

3 years ago