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inn [45]
3 years ago
13

An engine uses 5280 j of input heat to do 702 j of work.how much heat is rejected into the air

Physics
1 answer:
navik [9.2K]3 years ago
6 0

Answer:

4578 J

Explanation:

INPUT ENERGY = WORK + ENERGY REJECTED

or  ENERGY REJECTED = INPUT ENERGY - WORK

                                         = 5280-702

                                          = 4578J

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A sprinter is advised to reduced his speed slowly after completing his race.why
VARVARA [1.3K]

<span>The sprinter is advised to reduce his speed slowly after completing the race because of the power that is needed when the stoppage is down in a faster manner could be very great. This would translate to the great usage in gasoline. Also, the inertia of the vehicle is quiet high so it is hard to stop it very suddenly. </span>

5 0
3 years ago
A 6,000 kg train car is moving to the right at 10 m/s and connects to a 4,000-kg train car that wasn't moving. What is the veloc
vredina [299]

1) The final velocity of the two trains is 6 m/s to the right

2) It is an inelastic collision

Explanation:

1)

We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the two trains must be conserved before and after the collision.

Therefore we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 = 6,000 kg is the mass of the first train

u_1 = 10 m/s is the initial velocity of the first train

m_2 = 4,000 kg is the mass of the second train

u_2 = 0 is the initial velocity of the second train  (initially at rest)

v is the final combined velocity of the two trains

Solving the equation for v, we find the final velocity of the two trains:

v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(6000)(10)+0}{6000+4000}=6 m/s

2)

There are two types of collisions:

  • Elastic collision: in an elastic collision, both the total momentum and the total kinetic energy of the system are conserved
  • Inelastic collision: in an inelastic collision, only the total momentum is conserved, while the total kinetic energy is not (part of it is converted into thermal energy due to internal frictions)

To verify what type of collision is this, we can compare the total kinetic energy before and after the collision:

Before:

K=\frac{1}{2}m_1 u_1^2 = \frac{1}{2}(6000)(10)^2=300,000 J

After:

K=\frac{1}{2}(m_1 +m_2)v^2 = \frac{1}{2}(6000+4000)(6)^2=180,000 J

As we can see, the kinetic energy is not conserved, so this is an inelastic collision.

Learn more about momentum here:

brainly.com/question/7973509  

brainly.com/question/6573742  

brainly.com/question/2370982  

brainly.com/question/9484203  

#LearnwithBrainly

3 0
3 years ago
Points A [at (2, 3) m] and B [at (5, 7) m] are in a region where the electric field is uniform and given by E = (4i+3j)N/C. What
kkurt [141]

Answer:

- 144 V

Explanation:

A = (2, 3) m = 2 i + 3 j

B = (5, 7) m = 5 i + 7 j

Displacement vector = AB = B - A = (3 i + 4 j) m

Electric field, E = (4 i + 3 j ) N/C

V = - E . AB

V = - (4 i + 3 j) . (3 i + 4 j)

V = - (12 + 12) = - 144 V

5 0
2 years ago
A space probe is traveling in outer space with a momentum that has a magnitude of 3.87 x 107 kg·m/s. A retrorocket is fired to s
Virty [35]
Force = change in momentum / time, Force in opposite direction so negative
-1.41 x 10⁶ = (p₂ - 3.87 x 10⁷) / 9.55
p₂ = 2.52 x 10⁷ Ns
6 0
3 years ago
Through what angle in degrees does a 33 rpm record turn in 0.32 s?<br> 63°<br> 35°<br> 46°<br> 74°
Darina [25.2K]

Answer:

1 rev = 2(pi) rad  pi(rad) = 180 degrees

so 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s = 63.36 degrees

Explanation:

63.36 estimated to 63 so 63

6 0
2 years ago
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