Answer:
Explanation:
each grid corresponding 0.1s⁻¹.
0.2grid unit = 0.2×0.1 =0.02s⁻¹
distance of the star from telescope
d = 1/p
d= 1/0.02= 50 par sec
1par sec = 3.26 light year
1 light year = 9.5×10¹²km
3.26ly=3.084×10¹³km
d= 50×3.084×10¹³=1.55×10¹⁵km
Answer:
The point at which the electrical potential is zero is x = +0.33 m.
Explanation:
By definition the electrical potential is:
Where:
K: is Coulomb's constant = 9x10⁹ N*m²/C²
q: is the charge
r: is the distance
The point at which the electrical potential is zero can be calculated as follows:
(1)
q₁ is the first charge = +3 mC
r₁ is the distance from the point to the first charge
q₂ is the first charge = -6 mC
r₂ is the distance from the point to the second charge
By replacing r₁ = 1 - r₂ into equation (1) we have:
(2)
By solving equation (2) for r₂:
Therefore, the point at which the electrical potential is zero is x = +0.33 m.
I hope it helps you!
Answer:
Here is the answer. Hope this helps you!
Explanation:
Average velocity is the sum of initial and final velocity divided by 2. I t is the same as total Displacement divided by total time. Average velocity is calculated when the body is in non-uniform motion (also when total displacement and time is not given). The formula is as follows:
u + v/2 =
Average velocity = Average speed
during motion in a straight line. therefore, the above mentioned formula can be used for calculating average speed as well, when the direction is one and only the same, that is, during motion in a straight line. The S.I unit remains the same-
m/s.
Since velocity is vector, average VELOCITY is also vector. However, Average SPEED is scalar as speed is scalar. both can be equal only when the distance = displacement and when they are following the same direction of motion.