A force of 5N produces an acceleration of 8m/s2 on mass m1, and an acceleration of 24m/s2 on a mass m2. What acceleration would
1 answer:
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The direction of magnetic field is south-east and the magnitude is
×
.
Here, the magnitude of CD and BC will be cancelled, as they both are in the opposite direction and equal to each other.
the magnitude, towards the diagonal AC will result in CP, which is the direction of the electric field.
magnitude of electric field can be defined as :- The force per charge on the test charge is a straight forward way to define the size of the electric field.
To find the magnitude of the electric field use the formula
inserting the values,
×
×
×
/
×
N/C
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The distance covered by the rocket in the first 5 seconds is 7.13 m
Explanation:
In order to solve the problem, we have to find the acceleration of the rocket. We can do it by using Newton's second law, which states that the net force on the rocket is equal to the product between its mass (m) and its acceleration (a):
Where here we have:
is the time-dependent force
m = 49.5 kg is the mass
Solving for a(t),
This is the time-dependent acceleration of the rocket.
By integrating this expression, we find the velocity of the rocket at time t:
where we didn't add the constant term since the velocity at t = 0 is zero (the rocket starts from rest).
By integrating this expression, we then find an expression for the position of the rocket at time t:
Therefore, the distance covered by the rocket in the first t = 5.00 s is:
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