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Kitty [74]
3 years ago
9

What is the submarine's maximum safe depth in sea water? The pressure inside the submarine is maintained at 1.0 atm

Physics
1 answer:
Ludmilka [50]3 years ago
8 0
Hi! The answer is 15km I'm pretty sure
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If you are six feet tall how far back from a 3 foot mirror do you have to stand in order to see yourself completely?
OverLord2011 [107]

Answer:

you would have to stand 6 ft back

Explanation:

7 0
3 years ago
To practice Problem-Solving Strategy 16.1 Standing waves. An air-filled pipe is found to have successive harmonics at 800 HzHz ,
bazaltina [42]

Answer:

Length of the pipe = 53.125 cm

Explanation:

given data

harmonic frequency f1  = 800 Hz

harmonic frequency f2  = 1120 Hz

harmonic frequency f3  = 1440 Hz

solution

first we get here fundamental frequency that  is express as

2F = f2 - f1    ...............1

put here value

2F = 1120 - 800

F = 160 Hz

and

Wavelength is express as

Wavelength  = Speed ÷ Fundamental frequency    ................2

here speed of waves in air  = 340 m/s

so put here value

Wavelength  =340 ÷ 160

Wavelength   = 2.125 m

so

Length of the pipe will be

Length of the pipe = 0.25 × wavelength    ......................3

put here value

Length of the pipe = 0.25 × 2.125

Length of the pipe = 0.53125 m

Length of the pipe = 53.125 cm

7 0
3 years ago
A golf ball is struck with a five iron on level ground. it lands 100.0 m away 4.60 s later. what was the magnitude and direction
finlep [7]

consider the motion in x-direction

v_{ox} = initial velocity in x-direction = ?

X = horizontal distance traveled = 100 m

a_{x} = acceleration along x-direction = 0 m/s²

t = time of travel = 4.60 sec

Using the equation

X = v_{ox} t + (0.5) a_{x} t²

100 =  v_{ox} (4.60)

v_{ox} = 21.7 m/s


consider the motion along y-direction

v_{oy} = initial velocity in y-direction = ?

Y = vertical displacement  = 0 m

a_{y} = acceleration along x-direction = - 9.8 m/s²

t = time of travel = 4.60 sec

Using the equation

Y = v_{oy} t + (0.5) a_{y} t²

0 = v_{oy} (4.60) + (0.5) (- 9.8) (4.60)²

v_{oy} = 22.54 m/s

initial velocity is given as

v_{o} = sqrt((v_{ox})² + (v_{oy})²)

v_{o} = sqrt((21.7)² + (22.54)²) = 31.3 m/s

direction: θ = tan⁻¹(22.54/21.7) = 46.12 deg

6 0
3 years ago
Which variable is not required to calculate the gibbs free-energy change?
xxMikexx [17]
 All spontaneous processes release free energy
3 0
3 years ago
1000 millicoulombs of charge passes through a point. The amount of current passing through the point is
Rzqust [24]

The amount of current passing through the point is 1 A

The amount of current passing through the point can be calculated using the formula below.

⇒ Formula:

  • Q = i/t......................... Equation 1

⇒ Where:

  • Q = Charge
  • i = current
  • t = time.

⇒ Make "i" the subject of the equation.

  • i = Qt....................... Equation 2

From the question,

⇒ Given:

  • Q = 1000 millicoulombs = 1 coulombs
  • t = 1 seconds. (Assuming the time is 1 seconds)

⇒ Substitute these values into equation 2

  • i = 1/1
  • i = 1 A.

Hence, The amount of current passing through the point is 1 A.

Learn more about charges here: brainly.com/question/4158552

3 0
2 years ago
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