(a) 0.0068 Wb
Since the plane of the coil is perpendicular to the magnetic field, the magnetic flux through the coil is given by
where
N = 200 is the number of loops in the coil
B is the magnetic field intensity
is the area of the coil
At the beginning, we have
so the initial magnetic flux is
at the end, we have
so the final magnetic flux is
So the magnitude of the change in the external magnetic flux through the coil is
(b) 0.567 V
The magnitude of the average voltage (emf) induced in the coil is given by Faraday-Newmann law
where
is the variation of magnetic flux
is the time interval
Substituting into the formula, we find
(c) 0.142 A
The average current in the coil can be found by using Ohm's law:
where
I is the current
V is the voltage
R is the resistance
Here we have:
V = 0.567 V (induced voltage)
(resistance of the coil)
Solving for I, we find
Answer:
1m/s
Explanation:
Speed of a wave is expressed as;
Speed = frequency × wavelength
Given
Frequency = 2Hz
Wavelength = 0.5m
Required
Speed of the wave
Substitute
Speed = 2×0.5m
Speed = 1.0m/s
Hence the speed is 1.0m/s
Vector is perpendicular to x axis or i component.
Hence i component is 0
j component is 63.5
Because everybody in community needs to be smart & have some type of knowledge
Answer:
λ = 3 10⁻⁷ m, UV laser
Explanation:
The diffraction phenomenon is described by the expression
a sin θ = m λ
let's use trigonometry
tan θ = y / L
as in this phenomenon the angles are small
tan θ = 
= sin θ
sin θ = y / L
we substitute
a y / L = m λ
let's apply this equation to the initial data
a 0.04 / L = 1 600 10⁻⁹
a / L = 1.5 10⁻⁵
now they tell us that we change the laser and we have y = 0.04 m for m = 2
a 0.04 / L = 2 λ
a / L = 50 λ
we solve the two expression is
1.5 10⁻⁵ = 50 λ
λ = 1.5 10⁻⁵ / 50
λ = 3 10⁻⁷ m
UV laser
