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CaHeK987 [17]
3 years ago
14

ALGEBRA Find x and the measures of the unknown sides of each triangle.

Physics
1 answer:
valentina_108 [34]3 years ago
3 0

9514 1404 393

Answer:

  12.  x = 11; sides are 29

  13.  x = 5; sides are 25

Explanation:

12. The marked sides are equal length, so ...

  3x -4 = 2x +7

  x = 11 . . . . . . . . add 4-2x

  2x+7 = 2(11)+7 = 29 . . . side lengths

__

13. The marked sides are equal length, so ...

  6x -5 = 5x

  x = 5 . . . . . . . add 5-5x

  5x = 5(5) = 25 . . . side lengths

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Water flows through a cast steel pipe (k = 50 W m.K, ε = 0.8) with an outer diameter of 104mm and 2 mm wall thickness. Calculate
masha68 [24]

Answer:

The heat loss per unit length is   \frac{Q}{L}   = 2981 W/m

Explanation:

From the question we are told that

     The outer diameter of the pipe is d = 104mm = \frac{104}{1000} = 0.104 m

     The thickness is  D = 2mm = \frac{2}{1000} = 0.002m  

      The temperature  of water is  T = 90^oC = 90 + 273 = 363K  

      The outside air temperature is T_a = -10^oC = -10 +273 = 263K

        The water side heat transfer coefficient is z_1 = 300 W/ m^2 \cdot K

       The  heat transfer coefficient is  z_2 = 20 W/m^2 \cdot K

The heat lost per unit length is mathematically represented as

           \frac{Q}{L}   = \frac{2 \pi (T - Ta)}{ \frac{ln [\frac{d}{D} ]}{z_1}  +  \frac{ln [\frac{d}{D} ]}{z_2}}

Substituting values

         \frac{Q}{L}   = \frac{2 * 3.142 (363 - 263)}{ \frac{ln [\frac{0.104}{0.002} ]}{300}  +  \frac{ln [\frac{0.104}{0.002} ]}{20}}

           \frac{Q}{L}   = \frac{628}{0.2107}

           \frac{Q}{L}   = 2981 W/m

6 0
3 years ago
A) Define rest and motion?​
7nadin3 [17]

Answer:

Rest - a body is said to be at rest, if it does not change its position with respect to its surrounding with time. Motion - a body is said to be at motion, if it changes its position with time.

5 0
3 years ago
What is the temperature of a gas in which the atoms are moving very very slowly
Mice21 [21]
The temperature of a gas in which the atoms are moving slowly is (THE COLD). 




THAT'S IT! :)
4 0
3 years ago
Read 2 more answers
Micah knows that a car had a change in velocity of 15 m/s. To determine acceleration, Micah also needs the_______________
Tomtit [17]

Answer:

Duration of the total trip

Explanation:

Acceleration is defined as the rate of change of velocity of an object:

a=\frac{\Delta v}{\Delta t}

where

\Delta v is the change in velocity

\Delta t is the duration of the change in velocity

Acceleration is measured in meters per squared seconds, m/s^2. Also, we should note that acceleration is a vector quantity, so in order to completely define acceleration we also need to specify the direction.

5 0
3 years ago
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One side of a triangle is increasing at a rate of 5 cm/sec and a second side is increasing at a rate of 7 cm/sec. If the area of
Vanyuwa [196]

Answer:

The rate of angle is 26.25 rad/sec.

Explanation:

Given that,

First side of triangle a= 20 cm

Second side of triangle b= 50 cm

One side of a triangle is increasing at a rate = 5 cm/sec

Second side is increasing at a rate = 7 cm/s

Angle \theta=\dfrac{\pi}{3}=60^{\circ}

If the area of the triangle remains constant,

We need to calculate rate of angle

Using formula of area of triangle

A=\dfrac{1}{2}ab\sin\theta

On differentiating

\dfrac{dA}{dt}=\dfrac{1}{2}ab\cos\theta\dfrac{d\theta}{dt}+\dfrac{1}{2}a\sin\theta\dfrac{db}{dt}+\dfrac{1}{2}b\sin\theta\dfrac{da}{dt}

Put the value into the formula

0=\dfrac{1}{2}\times20\times50\cos60\dfrac{d\theta}{dt}+\dfrac{1}{2}\times20\sin60\times7+\dfrac{1}{2}\times50\sin60\times5

\dfrac{d\theta}{dt}=\dfrac{35\sqrt{3}\times\dfrac{25}{2}\sqrt{3}\times5}{250}

\dfrac{d\theta}{dt}=26.25\ rad/sec

Hence, The rate of angle is 26.25 rad/sec.

8 0
3 years ago
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